PHP For循环只运行一次

时间:2017-10-07 19:43:50

标签: php mysql arrays

我有一个for循环遍历和数组,运行与每个元素相关的数据库查询,然后调用一个打印出与之相关的东西的函数。该数组长度为12个元素,但for循环永远不会超过元素0.它不会出错或失败它只是在第一个元素之后没有做任何事情。我通过在每个循环周期的开头放置echo $x;echo $vendorsname[$x];来验证,确定它只向页面回显了0

$continuetill = count($vendorsname);

for ($x = 0; $x < $continuetill; $x++)
{

echo $x;
echo $vendorsname[$x];

$sql="SELECT low,mid,high,verlow,vermin,verhigh FROM vendors WHERE vendor = ".$x." ORDER BY id DESC LIMIT 1";

if ($result=mysqli_query($conn,$sql))
  {
  // Fetch one and one row
  while ($row=mysqli_fetch_row($result))
    {
      $low = $row[0];
      $mid = $row[1];
      $high = $row[2];
      $verlow = $row[3];
      $vermid = $row[4];
      $verhigh = $row[5];



      if(($low > $mid) && ($low > $high))
      {
        likely295Message($vendorsname[$x]);
      }
      elseif (($high > $low) && ($high > $mid) && ($high < 15))
      {
        possibly300Message($vendorsname[$x]);
      }
      elseif (($high > $low) && ($high > $mid) && ($high >= 15))
      {
        likely300Message($vendorsname[$x]);
      }
      elseif (($mid > $low) && ($mid > $high))
      {
        likely296Message($vendorsname[$x]);

      }else
      {
        unknownMessage($vendorsname[$x]);
      }


      if(($verlow != 0) || ($vermid != 0) || ($verhigh != 0))
      {
        if(($verlow > $vermid) && ($verlow > $verhigh))
        {
          verified295Message($vendorsname[$x]);
          changeBackgroundBack($vendorsname[$x]);
          changeImage($vendorsname[$x]);

        }
        elseif (($verhigh > $verlow) && ($verhigh > $vermid))
        {
          verified300($vendorsname[$x]);
          changeBackground($vendorsname[$x]);
          changeImage($vendorsname[$x]);
        }
        elseif (($vermid > $verlow) && ($vermid > $verhigh))
        {
          verified296($vendorsname[$x]);
          changeBackgroundBack($vendorsname[$x]);
          changeImage($vendorsname[$x]);
        }
      }

    }

  mysqli_free_result($result);
}
}

1 个答案:

答案 0 :(得分:0)

确保您已启用错误显示。在脚本的开头添加:

ini_set('display_errors', 1);

确保您没有任何错误。