Question

我有两个表table1和table2 ItemId，这是表2的关键

表1

|itemsId | Item | Quantity|
----------------------------
1 | item | 20

表2

|ItemId | Status | Quantity 
---------------------------
1 |Item Out| 5

我在table1 - table2中减去数量，并在New Column Called Remain中分配值，现在问题是我想要将结果列加入表1和table2

ItemId | Item | Quantity | Remaining |
---------------------------------------
1 | item | 20 | 15

我试过这个

SELECT *
FROM (select i.ItemsId,i.Date,s.[Item Name],i.Quantity,i.[Recieved By],i.[From],i.[Reference No]
      from Store s inner join
           ItemsMovement i
           on s.ItemsId = i.ItemsId
      group by i.ItemsId
     ) T1 INNER JOIN 
     (select SUM(a.Quantity - b.Quantity) AS Remaining
      FROM Store a inner join
           ItemsMovement b
           on a.ItemsId = b.ItemsId 
      where b.Status ='Items In'
      group by a.ItemsId
     ) T2

Answer 1

我认为你可以通过条件聚合更轻松地做你想做的事情：

select i.ItemsId, i.Date, s.[Item Name], i.Quantity, i.[Recieved By],
       i.[From],i.[Reference No],
       sum(case when i.Status = 'Items In' then s.Quantity - i.Quantity end) as remaining
from Store s inner join
     ItemsMovement i
     on s.ItemsId = i.ItemsId
group by i.ItemsId;

如何从两个选择查询中加入结果

1 个答案: