Question

我将从图库中挑选的图片转换为其网址，如此...

func imagePickerController(_ picker: UIImagePickerController, didFinishPickingMediaWithInfo info: [String : Any]) {

if let image = info[UIImagePickerControllerOriginalImage] as? UIImage {
UIImageWriteToSavedPhotosAlbum(image, self, #selector(image(_:didFinishSavingWithError:contextInfo:)), nil)

let imageURL = info[UIImagePickerControllerReferenceURL] as? NSURL
let imageName = imageURL?.lastPathComponent
let documentDirectory = NSSearchPathForDirectoriesInDomains(.documentDirectory, .userDomainMask, true).first!
let photoURL = NSURL(fileURLWithPath: documentDirectory)
self.localPath = photoURL.appendingPathComponent(imageName!)

do {
   try UIImageJPEGRepresentation(image, 1.0)?.write(to: localPath!)
   print("File Saved")
   imageArray.append(image)

   } catch { //Error }
   self.collectionView.reloadData()
   } else {  //Error here }
        self.dismiss(animated: true, completion: nil)
  }

现在，如果我有2个图像，我想逐个将它们作为参数传递给我的API调用。我这样做......

for imgURL in imageArray {
            let url = "http://myapp.com/vw/images_upload"
            let headers = [ "Content-Type":"application/x-www-form-urlencoded"]

     let Parameters =
                [
                 "image": imgURL,
                 "seller_id": id
                ] as [String : Any]

Alamofire.request(url, method: .post, parameters: Parameters, encoding: URLEncoding.httpBody, headers: headers)

                .responseJSON { (response) in
                    if let httpResponse = response.response {
                        print("error \(httpResponse.statusCode)")

                        if httpResponse.statusCode == 200 {
                            if let result = response.result.value as? [String:Any] {
                                if result["success"] as! Int == 0 {
                                    print("Something went wrong!")    
                                }  else if result["success"] as! Int == 1 {
                                    print("UPLOADED IMAGE SUCCESSFULLY!!")
                              }}}}}}

但是在imgURL中的参数中，我没有得到图片的网址。上面我得到了localPath中的网址。但我无法遍历localPath，因为它会出错。另外，在imageArray中，我传递了不是网址格式的图片......它采用以下格式：<UIImage: 0x60800009f9f0> size {4288, 2848} orientation 0 scale 1.000000...如何将网址格式传递到{{} 1}}，我无法理解。这可能是问题吗？

另外，我如何获取图像的网址，以便将其传递给API调用...？请帮忙......

Answer 1

您在我的问题中理解的是，您正在将图像设置为imageview，并且您希望将该图像的路径传递给api。所以我写了一个函数来做同样的调整大小，你可以根据自己的需要避免或修改。

因此，传递图像选择器拾取的图像和默认名称字符串（例如：＆＃34; image1＆＃34;），您将得到图像路径/网址作为回报 func storeImage（image：UIImage，fileName：String） - ＆gt;字符串{ var resizedImage = image

     func storeImage(image:UIImage, fileName:String) -> String {
    var resizedImage = image

    if (image.size.width > 200) {
        let width = 200.0 as CGFloat
        let height = image.size.height * width / image.size.width
        resizedImage = image.scaleImage(toSize: CGSize(width: width, height: height))!
    }
    else if (image.size.height > 200) {
        let height = 200.0 as CGFloat
        let width = image.size.width * height / image.size.height
        resizedImage = image.scaleImage(toSize: CGSize(width: width, height: height))!
    }

    let imageData = NSData(data:UIImagePNGRepresentation(resizedImage)!)
    let paths = NSSearchPathForDirectoriesInDomains(FileManager.SearchPathDirectory.documentDirectory, FileManager.SearchPathDomainMask.userDomainMask, true)
    let docs: String = paths[0]
    let fullPath = docs.stringByAppendingPathComponent(path: fileName)

    _ = imageData.write(toFile: fullPath, atomically: true)
    return fullPath
}

在图库

1 个答案: