Question

fixed

用户将苏打水洒在眼镜之间。用户点击三个可用的第一个JButton确定＆＃34;来自＆＃34;初始玻璃和用户点击三个可用的第二个JButton决定了＆＃34;到＆＃34;目的地玻璃。

如何确定用户点击的特定两个JButton？每当用户点击三个JButtons中的两个时，我想将与这两个JButton相关联的字符串存储在＆＃34;来自＆＃34;和＆＃34;到＆＃34;变量。

有没有办法做到这一点？

Answer 1

制作ActionListener并使用JButton#addActionListener将其添加到所有三个按钮。该事件有一个您可以使用的源字段。

ActionListener listener = new ActionListener() {
    JButton first;
    JButton second;

    @Override
    public void actionPerformed(ActionEvent e) {
        if(first == null)
        {
            first = (JButton) e.getSource();
        }
        else
        {
            second = (JButton) e.getSource();

            // do something

            // clean up
            first = null;
            second = null;
        }   
    }
};


glass1.addActionListener(listener);
glass2.addActionListener(listener);
glass3.addActionListener(listener);

处理侦听器内部的逻辑有点脏，但这就是想法。

Answer 2

firstbutton.addActionListener(new ActionListener() { 
  public void actionPerformed(ActionEvent e) { 
    //do something here first button is clicked
  } 
} );

你可以将监听器添加到这样的按钮中。并使用类变量来跟踪单击按钮的次数。

例如：

public class GUIControl {
public static void main(String[] args) {
    javax.swing.SwingUtilities.invokeLater(new Runnable() {
        public void run() {
            showGUI();
        }
    });
}



public static void showGUI() {  
    JFrame frame = new JFrame("MyFrame");
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    frame.setLayout(new BorderLayout());

    JButton glass1 = new JButton("glass1");
    JButton glass2 = new JButton("glass2");
    JButton glass3 = new JButton("glass3");

    String from = "";
    String to = "";
    int click_count = 0;


glass1.addActionListener(new ActionListener() { 
  public void actionPerformed(ActionEvent e) { 
    if(click_count ==0)
    {
       from = "glassX";
       click_count = 1;
    }else if(click_count ==1)
    {
       from = "glassY";
       click_count = 0;
    }
  } 
} );

glass2.addActionListener(new ActionListener() { 
  public void actionPerformed(ActionEvent e) { 
    if(click_count ==0)
    {
       from = "glassX";
       click_count = 1;
    }else if(click_count ==1)
    {
       from = "glassY";
       click_count = 0;
    }
  } 
} );

glass3.addActionListener(new ActionListener() { 
  public void actionPerformed(ActionEvent e) { 
    if(click_count ==0)
    {
       from = "glassX";
       click_count = 1;
    }else if(click_count ==1)
    {
       from = "glassY";
       click_count = 0;
    }
  } 
} );

    frame.getContentPane().add(glass1);
    frame.getContentPane().add(glass2);
    frame.getContentPane().add(glass3);
    frame.pack();
    frame.setVisible(true);

    // I want to store the first two clicks in these variables
}

确定用户进行的两次点击的顺序

2 个答案: