在连接的基础上从不同的表中选择记录计数

Question

我想获取用户在不同表中输入的记录数。 DB的架构是：

+-----------------------+  
| Survey Master         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   |  
| Username       |      |
| FamilyMasterId | FK   |
+----------------+------+

+------------+------+  
| Family Master     |  
+------------+------+   
| Field      | Key  |  
+------------+------+  
| id         | PK   |   
+------------+------+

+-----------------------+  
| Family Detail         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| FamilyMasterId | FK   |   
+----------------+------+

+-----------------------+  
| Travel Master         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| FamilyDetailId | FK   |   
+----------------+------+

+-----------------------+  
| Travel Detail         |  
+----------------+------+   
| Field          | Key  |  
+----------------+------+  
| id             | PK   | 
| TravelMasterId | FK   |   
+----------------+------+

我希望看到每个用户在每个表中创建的记录数量如下：

  Username   SurveyMaster   FamilyMaster   FamilyDetail   TravelMaster   TravelDetail  
 ---------- -------------- -------------- -------------- -------------- -------------- 
  User001    59             47             36             26             12            
  User002    88             76             64             42             25            
  User003    49             44             35             25             15            
  User004    77             69             55             45             37  

查看以下链接后：

1. Find Records from Different Tables
2. Select count(*) from multiple tables
3. http://www.sqlines.com/mysql/how-to/join-different-tables-based-on-condition
4. http://www.informit.com/articles/article.aspx?p=30875&seqNum=5
5. SQL: Combine Select count(*) from multiple tables

我能够编写此查询但它在所有列中提供相同的记录：

SELECT USERNAME, COUNT(USERNAME) SURVEYMASTER, COUNT(USERNAME) FAMILYMASTER, COUNT(USERNAME) FAMILYDETAIL, COUNT(USERNAME) TRAVELMASTER, COUNT(USERNAME) TRAVELDETAIL FROM 
((SELECT CREATEUSER USERNAME FROM SURVEYMASTER
) 
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
) 
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
)
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID
)
UNION ALL
(SELECT SM.CREATEUSER USERNAME FROM SURVEYMASTER SM
INNER JOIN FAMILYMASTER FM ON FM.ID = SM.FAMILYMASTERID
INNER JOIN FAMILYDETAIL FD ON FM.ID = FD.FAMILYMASTERID
INNER JOIN TRAVELMASTER TM ON FD.ID = TM.FAMILYDETAILID
INNER JOIN TRAVELDETAIL TD ON TM.ID = TD.TRAVELMASTERID
)
) T
GROUP BY USERNAME
ORDER BY USERNAME

修改

以下是关系描述：

1. FamilyMasterId是SurveyMaster和FamilyDetail中的外键 表。
2. FamilyDetailId是TravelMaster表中的外键。
3. TravelMasterId是TravelDetail表中的外键。

Answer 1

如果我们考虑性能但是它可以提供所需的结果，这可能不是完美的解决方案

SELECT  sm.Username ,
        COUNT(*) SurveyMaster ,
        COUNT(FamilyMasterId) FamilyMaster ,
        fd.FamilyDetail ,
        tm.TravelMaster ,
        td.TravelDetail
FROM    SurveyMaster sm
        JOIN ( SELECT   Username ,
                        COUNT(fd.id) FamilyDetail
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
               GROUP BY Username
             ) fd ON sm.Username = fd.Username
        JOIN ( SELECT   Username ,
                        COUNT(tm.id) TravelMaster
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
                        JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId
               GROUP BY Username
             ) tm ON sm.Username = tm.Username
        JOIN ( SELECT   Username ,
                        COUNT(td.id) TravelDetail
               FROM     SurveyMaster sm
                        JOIN FamilyMaster fm ON sm.FamilyMasterId = fm.Id
                        JOIN FamilyDetail fd ON fm.id = fd.FamilyMasterId
                        JOIN TravelMaster tm ON fd.Id = tm.FamilyDetailId
                        JOIN TravelDetail td ON tm.Id = td.TravelMasterId
               GROUP BY Username
             ) td ON sm.Username = td.Username
GROUP BY sm.Username ,
        fd.FamilyDetail ,
        tm.TravelMaster ,
        td.TravelDetail;