Question

我正在尝试在MySql 5.1.41中执行触发器语句，但是我收到的错误超出了我的理解范围。任何帮助将不胜感激。

以下是触发代码：

create TRIGGER populate_modality_trigger AFTER INSERT on series
FOR EACH ROW BEGIN
DECLARE x int;

select count(*) into x from lu_modality_alias l WHERE l.modality=NEW.modality;
IF (x  =0 OR x is NULL) THEN
    INSERT INTO lu_modality_alias 
    set modality = NEW.modality,
    modality_alias  = NEW.modality
;
END if;
end;

当我运行上面的代码时，我收到以下错误：

MySQL说：文档＃1064 - 你的SQL语法有错误;检查与MySQL服务器版本对应的手册，以便在第3行的''附近使用正确的语法

有趣的是，当我从Naviacat查询编辑器执行相同的代码时，它会成功运行并创建触发器。但是phpMyAdmin sql也失败了。

Answer 1

您需要更改分隔符，以便MySql解析器不会在第一个分号结束时解析CREATE语句

delimiter //

create TRIGGER populate_modality_trigger AFTER INSERT on series
FOR EACH ROW BEGIN
DECLARE x int;

select count(*) into x from lu_modality_alias l WHERE l.modality=NEW.modality;
IF (x  =0 OR x is NULL) THEN
    INSERT INTO lu_modality_alias 
    set modality = NEW.modality,
    modality_alias  = NEW.modality
;
END if;
end //

delimiter ;

MySql触发器语法错误1064空单引号

1 个答案: