单击选择器时如何停止滚动功能？

Question

当滚动到该页面上的相应部分时，导航中的各个父菜单项将突出显示。

现在，如果访问者决定单击父菜单项而不是滚动，则父菜单项不会正确突出显示，因为滚动功能会跟随并突出显示上一个父菜单项。

点击$（＆＃39; .nav a）后如何停止滚动功能？

＆＃13;

＆＃13;

jQuery(function($) {

  var services = $('.services').offset().top;
  var locations = $('.locations').offset().top;
  var about = $('.about').offset().top;
  var contact = $('.contact').offset().top;

  $(window).scroll(function() {
    var scrollPos = $(document).scrollTop();
    if (scrollPos >= services && scrollPos < locations) {
      $('.nav a').removeClass('active');
      $('.wsite-nav-2 a').addClass('active');
    } else if (scrollPos >= locations && scrollPos < about) {
      $('.nav a').removeClass('active');
      $('.wsite-nav-3 a').addClass('active');
    } else if (scrollPos >= about && scrollPos < contact) {
      $('.nav a').removeClass('active');
      $('.wsite-nav-4 a').addClass('active');
    } else if (scrollPos >= contact) {
      $('.nav a').removeClass('active');
      $('.wsite-nav-5 a').addClass('active');
    } else if (scrollPos <= services) {
      $('.nav a').removeClass('active');
      $('.wsite-nav-1 a').addClass('active');
    }
  });

  $('.wsite-nav-1 a').addClass('active');

  $('.nav a').click(function() {
    $('.nav a, .wsite-nav-1 a').removeClass('active');
    $(this).addClass('active');
  });

});

＆＃13;

.active {
  background: #f0b823;
}

＆＃13;

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="nav">
  <ul>
    <li class="wsite-nav-1"><a href="#">Home</a></li>
    <li class="wsite-nav-2"><a href="#">Services</a></li>
    <li class="wsite-nav-3"><a href="#">Locations</a></li>
    <li class="wsite-nav-4"><a href="#">About</a></li>
    <li class="wsite-nav-5"><a href="#">Contact</a></li>
  </ul>
</div>

<div class="content">
  <div class="anchor">
    <a name="A" class="anchor-link services"></a>
  </div>
  <div class="anchor">
    <a name="B" class="anchor-link locations"></a>
  </div>
  <div class="anchor">
    <a name="C" class="anchor-link about"></a>
  </div>
  <div class="anchor">
    <a name="D" class="anchor-link contact"></a>
  </div>
</div>

＆＃13;

＆＃13;

＆＃13;

Answer 1

我可能会做这样的事情来快速解决。

＆＃13;

＆＃13;

var isClicked = false;

$(window).scroll(function() {

  if (isClicked) {
    return false;
  }

  var scrollPos = $(document).scrollTop();
  if (scrollPos >= services && scrollPos < locations) {
    $('.nav a').removeClass('active');
    $('.wsite-nav-2 a').addClass('active');
  } else if (scrollPos >= locations && scrollPos < about) {
    $('.nav a').removeClass('active');
    $('.wsite-nav-3 a').addClass('active');
  } else if (scrollPos >= about && scrollPos < contact) {
    $('.nav a').removeClass('active');
    $('.wsite-nav-4 a').addClass('active');
  } else if (scrollPos >= contact) {
    $('.nav a').removeClass('active');
    $('.wsite-nav-5 a').addClass('active');
  } else if (scrollPos <= services) {
    $('.nav a').removeClass('active');
    $('.wsite-nav-1 a').addClass('active');
  }
});

$('.wsite-nav-1 a').addClass('active');

$('.nav a').click(function() {
  isClicked = true;
  $('.nav a, .wsite-nav-1 a').removeClass('active');
  $(this).addClass('active');
});

＆＃13;

＆＃13;

＆＃13;

更新

这是此问题的可接受解决方案 - https://codepen.io/bb027/pen/VMQdXL