我有两个数组
String[] names = {“bob”, “rob”}; //There are multiple arrays for various scenarios names1, names2 and so on…
String[] features = {“age”, “weight”}; //There are multiple array for various scenarios features1 features2 and so on…
和类中的HashMap,其中包含键和值 年龄,体重,性别,职业......
我从中得到这样的价值:
public ClassToGetValues (String name) {
public String getValue(String key) {
return map.get(key);
}
private void buildMap(Paramenter1 paramenter1, Paramenter2, paramenter2) {
map.put("name", someFunction());
map.put(....
}
}
我使用这些数组和地图来打印以下内容:
bob 30yr 160lbs
抢40升170磅
private static void printMethod(String[] names, String[] features) {
for (String name : names) {
ClassToGetValues classToGetValues = new ClassToGetValues(name);
for (String feature : features) {
System.out.print(classToGetValues.getValue(feature) + " ");
}
System.out.println();
}
}
现在我想创建一些像
这样的方法方法1
public String criteriaOne(int age, int weight) {
if (age > 35 && weight > 160) {
// "Do something";
}
return names;
}
方法2
public String criteriaTwo(int age, String gender) {
if (age <70 && gender == “male”) {
// "Do something";
}
return names;
}
如何开始创建这些方法?
答案 0 :(得分:0)
在Java中,您将创建一个Person类来存储与人相关的数据,而不是将这些数据丢失地保存在不同的数据结构中。好吧,可能有一些外部约束使你这样做,即使java不是那样用的。我的建议是,创建一个类并保存该类型的列表或映射:
public class Person {
private String name;
private int age;
private double weight;
public Person(String name, int age, double weight) {
this.name = name;
this.age = age;
this.weight = weight;
}
public String getName() {
return this.name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return this.age;
}
public void setAge(int age) {
this.age = age;
}
public double getWeight() {
return this.weight;
}
public void setWeight(double weight) {
this.weight = weight;
}
@Override
public String toString() {
String s = String.format("Person %s is %d years old and weighs %f lbs", name, String.valueOf(age), String.valueOf(double));
return s;
}
然后您创建一个List<Person>
,添加一些Person
并打印出每个Person
的数据,如
List<Person> persons = new ArrayList<Person>();
persons.add(new Person("Bob", 23, 160);
persons.add(new Person("Rob", 20, 120);
for (Person p : persons) {
System.out.println(p.toString());
}