Question

我遇到了这个功能的问题。有人可以帮我解决一下吗？

def string_list(L):
    '''(list of str) -> list of list
    Given a list of strings where each string has the format:
    'name, grade, grade, grade, ...' return a new list of 
    lists where each inner list has the format :
    [name (str), grade, grade, grade, ...] where the name 
    is a string and the grades are floats.

>>> string_list(['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98'])
[['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]
'''
new_string_list = []
for grades in L:
    if grades.isnumeric():
        grades = float(grades)
        new_string_list.append([grades])
        for name in L:
            if name.isalpha():
                new_string_list.append([name])
return new_string_list.append([name, grades])

Answer 1

你走了：

students = ['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']
result = []
for item in students:
  parts = item.split(', ')
  item_result = parts[:1] + [float(y) for y in parts[1:]]
  result.append(item_result)
print(result)
# [['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]

Answer 2

int

输出：

stringList = ['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']
[ [j[0]]+[float(k) for k in j[1:]] for j in [i.split(', ') for i in stringList] ]

Answer 3

只是列表理解：

>>> a
['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']
>>> r=[[float(j) if j.replace('.', '').isdigit()  else j for j in i.split(", ")] for i in a]
>>> r
[['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]

如果检查索引：

>>> a=['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']
>>> r=[[float(j) if i.split(", ").index(j)!=0 else j for j in i.split(", ")] for i in a]
>>> r
[['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]

Answer 4

您可以尝试这样的事情：

双线解决方案：

list_1=['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']

split_it=[str(i).replace(",","").split() for i in list_1]


print([i[:1]+[float(j) for j in i[1:]] for i in split_it])

输出：

[['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]

详细解决方案：

第一步拆分你的字符串，以便我们可以迭代每个元素：

split_it=[]  #storing new splited result here 

for i in list_1:
    split_it.append(str(i).replace(",","").split())

print(split_it)
[['Anna', '50', '90', '80'], ['Bill', '60', '70'], ['Cal', '98.5', '100', '95.5', '98']]

现在，下一步是遍历每个子列表并保留自其str之后的第一个元素，并将其余部分转换为float：

我建议你在使用列表理解之前应该知道列表理解是如何工作的：

list=[i for i in a]

与：
相同

list=[]
for i in a:
    list.append(i)

现在回到解决方案：

float_list=[]
for i in split_it:
    sub_list=[]
    for j in i[1:]:
        sub_list.append(float(j))

    float_list.append(i[:1]+sub_list)

print(float_list)

所有组合：

list_1=['Anna, 50, 90, 80', 'Bill, 60, 70', 'Cal, 98.5, 100, 95.5, 98']


split_it=[]  #storing new splited result here

for i in list_1:
    split_it.append(str(i).replace(",","").split())


float_list=[]
for i in split_it:
    sub_list=[]
    for j in i[1:]:
        sub_list.append(float(j))

    float_list.append(i[:1]+sub_list)

print(float_list)

输出继电器：

[['Anna', 50.0, 90.0, 80.0], ['Bill', 60.0, 70.0], ['Cal', 98.5, 100.0, 95.5, 98.0]]

返回一个名称和等级转换为float的新列表？

4 个答案: