我有以下json数据
{
"apps": [
{
"thingA": "aaaaaa",
"thingB": "bbbbbb",
"thingC": "cccccc",
"thingD": {
"thingD1": "d1d1d1d1",
"thingD2": "d2d2d2d2"
},
"thingE": "eeeeee",
"out_file": "ffffff"
},
{
"thingA": "aaaaaa",
"thingB": "bbbbbb",
"thingC": "cccccc",
"thingD": {
"thingD1": "d1d1d1d1",
"thingD2": "d2d2d2d2"
},
"thingE": "eeeeee",
"out_file": "ffffff"
},
{
"thingA": "aaaaaa",
"thingB": "bbbbbb",
"thingC": "cccccc",
"thingD": {
"thingD1": "d1d1d1d1",
"thingD2": "d2d2d2d2"
},
"thingE": "eeeeee",
"out_file": "ffffff"
}
]
}
我尝试使用json_decode将其转换为PHP中的数组，根据数组位置/索引从数组中删除项目，然后使用json_encode将数组转换回JSON。
要修改数组，请使用以下PHP命令
unset($configuration_Array->{'apps'}[$i]);
其中$ i是要删除的项目的索引位置。
除了在最终（输出）JSON数据中，我注意到我将每个＆＃34; apps＆＃34;添加了关键值，所以它的工作几乎完全正常。对象（注意每个对象之前的数字键＆＃39;）{
"apps":{
"1":{
"thingA":"aaaaaa",
"thingB":"bbbbbb",
"thingC":"cccccc",
"thingD":{
"thingD1":"d1d1d1d1",
"thingD2":"d2d2d2d2"
},
"thingE":"eeeeee",
"out_file":"ffffff"
},
"2":{
"thingA":"aaaaaa",
"thingB":"bbbbbb",
"thingC":"cccccc",
"thingD":{
"thingD1":"d1d1d1d1",
"thingD2":"d2d2d2d2"
},
"thingE":"eeeeee",
"out_file":"ffffff"
},
"3":{
"thingA":"aaaaaa",
"thingB":"bbbbbb",
"thingC":"cccccc",
"thingD":{
"thingD1":"d1d1d1d1",
"thingD2":"d2d2d2d2"
},
"thingE":"eeeeee",
"out_file":"ffffff"
}
}
}
当我执行json_encode或事后删除它以便数据结构与原始版本完全相同时，如何避免添加？