Question

我执行php脚本来显示随机数据。我使用ajax get从php脚本获取数据并继续每1秒从php脚本获取数据。如果计数更多或者eqaul为4，我也会删除最后一行.Howwever，我的输出是向后的。我想在旧数据之前附加新数据。

php脚本

<?php


$countryarr = array("UNITED STATES", "INDIA", "SINGAPORE","MALAYSIA","COLOMBIA","THAILAND","ALGERIA","ENGLAND","CANADA","CHINA", "SAUDI ARABIA");
$length = sizeof($countryarr)-1;
$random = rand(0,$length);
$random1 = rand(0,$length);

$random_srccountry = $countryarr[$random];
$random_dstcountry = $countryarr[$random1];
echo "<div>[X] NEW ATTACK: FROM [".$random_srccountry."] TO [".$random_dstcountry."]  </div>";
?>

html代码

<html>
<head>
<title>Add new data</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<style>
#result {
    width: 500px;
    height:500px;
    border-style: solid;
    border-color: black;
}
</style>
</head>
<body>
<div id="result"></div>

<script>
var $auto_refresh = setInterval(function() {
    var $count = $('#result div').length;

    while ($count >= 4) {
    $('result div:last-child').remove();
    $count = $('#result div').length;
    }
    updateServer();
}, 1000);
//Remove last div if the count is more than 4
function updateServer() {
    $.get({
            url: 'randomData.php',
            dataType: 'text',
            success: randomdata
        });
}

function randomdata(val) {
        $('#result').append(val); //i want to insert before in other words new data appear at the top and old data remain down
}
</script>
</body>
</html>

我想过使用before或insertbefore在旧数据之前插入新数据。我之前也使用过节点插入。它不起作用。请帮我。谢谢..

Answer 1

您必须使用jquery中的prepend()：

function randomdata(val) {
    $('#result').prepend(val);
}

修改

我注意到其他错误：$('result div:last-child').remove();应为$('#result div:last-child').remove();

这可能就是为什么它不会改变，当它在4个div时它不会删除并重做计数，所以你会陷入困境......从下面修复应解决问题

如何在旧数据之前而不是之后插入新数据

1 个答案: