如何使用newtonsoft.json嵌套

Question

我试图用Newtonsoft.JSON包解析JSON。

string jsonData =
 "{\"name\":\"olga\",\"tokenmode\":\"bearer\",\"expires\":9483,\"refresh\":\"{\\\"Id\\\":\\\"alla-ieih-8493j-2455d\\\",\\\"Id\\\":\\\"94094-3838485-kdooj4u\\\"}\",\"status\":\"10\",\"namestatus\":\"5\"}";


 dynamic aa = JsonConvert.DeserializeObject(jsonData);

var name = aa.name.tostring(); //Outputs olga

var id = aa.refresh.Id.ToString(); //Gives error

问题是如何访问Id数据？

Answer 1

您必须添加

dynamic refresh = JsonConvert.DeserializeObject(aa.refresh.ToString());

Answer 2

创建一个类：

class Player
{
    public Guid ID { get; set; }
    public string Name { get; set; }
    public TimeSpan Elapsed { get; set; }

    [JsonConstructor]
    public Player(Guid id, string name, TimeSpan elapsed)
    {
        this.ID = id;
        this.Name = name;
        this.Elapsed = elapsed;
    }
    public Player(string name, TimeSpan elapsed)
    {
        this.ID = Guid.NewGuid();
        this.Name = name;
        this.Elapsed = elapsed;
    }
}

询问对象：

Player player = JsonConvert.DeserializeObject<Player>(jsonstring);

询问对象列表：

List<Player> players = JsonConvert.DeserializeObject<List<Player>>(jsonstring);

Answer 3

你必须这样做：

var id = aa.refresh[0].Id.ToString();