Question

我试图制作一个收银机计算器应用程序，帮助我更快地从寄存器中赚钱。例如：我可以输入20美元的单数，而不是将所有20美元的票据相加，而应用程序可以计算总数。这是我的代码，我使用了Struct和函数，但运行代码时出错。感谢

struct Money {
    oneCent: Double
    fiveCent: Double
    tenCent: Double
    quater: Double
    fiftyCent: Double
    rollCent: Double
    rollFive: Double
    rollTen: Double
    rollQuater: Double
    dollarCoin: Double
    dollar: Double
    fiveDollar: Double
    tenDollar : Double
    twentyDollar: Double
    fiftyDollar: Double
    hundredDollar: Double
    oneCent: Double
}

func moneyCalcualate (value at : Money, copies: Double){

    var total : Double = 0.00
    for i in at{
        switch i {
           case oneCent : total = 0.01 * copies
           case fiveCent : total = 0.05 * copies
            case tenCent : total = 0.10 * copies
            case  quater : total = 0.25 * copies
            case  fiftyCent : total = 0.50 * copies
            case  rollCent: total = 0.01 * copies
            case  rollFive: total = 0.01 * copies
            case  rollTen : total = 0.01 * copies
            case  rollQuater : total = 10.00 * copies
            case  dollarCoin : total = 1.00 * copies
            case  dollar : total = 1.00 * copies
            case  fiveDollar : total = 5.00 * copies
            case  tenDollar : total = 10.00 * copies
            case twentyDollar : total = 20.00 * copies
            case fiftyDollar : total = 50.00 * copies
            case hundredDollar : total = 100.00 * copies

        }
    }
    return total
}


moneyCalcualate(value: quater, copies: 2.0)

Answer 1

这是enum的典型案例。将所有货币类型声明为案例并为每个类型分配原始值。然后，您可以创建一个函数，该函数将返回当前类型的给定份数的总数。

以下是一个例子：

enum Money: Double {
    case oneCent = 0.01
    case fiveCent = 0.05
    case tenCent = 0.1
    case quarter = 0.25

    func total(numberOfCopies: Int) -> Double {
        return self.rawValue * Double(numberOfCopies)
    }
}

你这样称呼它：

let moneyInFiveCents = Money.fiveCent
let fiveCents = moneyInFiveCents.total(numberOfCopies: 5)
print(fiveCents)
// prints 0.25

let moneyInQuarters = Money.quarter
let quarters = moneyInQuarters.total(numberOfCopies: 5)
print(quarters)
// prints 1.25

print(fiveCents + quarters)
// prints 1.5

Answer 2

你可以这样试试..

enum Money {
case oneCent
case fiveCent
case tenCent
case quater
case fiftyCent
case rollCent
case rollFive
case rollTen
case rollQuater
case dollarCoin
case dollar
case fiveDollar
case tenDollar 
case twentyDollar
case fiftyDollar
case hundredDollar



static let all : [Money] = [.oneCent , .fiveCent , .tenCent , .quater, .fiftyCent, .rollCent, .rollFive, .rollTen, .rollQuater, .dollarCoin, .dollar, .fiveDollar, .tenDollar, .twentyDollar, .fiftyDollar, .hundredDollar]
}

func moneyCalcualate (value at : Money, copies: Double) -> Double{


var total : Double = 0.00


switch at {
case .oneCent : total = 0.01 * copies
case .fiveCent : total = 0.05 * copies
case .tenCent : total = 0.10 * copies
case .quater : total = 0.25 * copies
case  .fiftyCent : total = 0.50 * copies
case  .rollCent: total = 0.01 * copies
case  .rollFive: total = 0.01 * copies
case  .rollTen : total = 0.01 * copies
case  .rollQuater : total = 10.00 * copies
case  .dollarCoin : total = 1.00 * copies
case .dollar : total = 1.00 * copies
case  .fiveDollar : total = 5.00 * copies
case  .tenDollar : total = 10.00 * copies
case .twentyDollar : total = 20.00 * copies
case .fiftyDollar : total = 50.00 * copies
case .hundredDollar : total = 100.00 * copies

}

return total
}


moneyCalcualate(value: .quater, copies: 2.0)

希望它有所帮助!!

使用Struct和函数时在swift 3中遇到问题

2 个答案: