Question

您好我在使用mapstruct从Child Source类设置它时在DTO中为List操作获取null。有人可以帮我解决这个问题。请在这里找到我的代码

实体类：

public class Source {
    int id;
    String name;
    List<ChildSource> childSource;
    //getters and setters
}

public class ChildSource {
    String code;
    String action;
    //getters and setters   
}

DestinationDTO：

public class TargetDTO{
    int sNo;
    String mName;
    List<String> actions;
    //getters and setters  
}

MApper Class：

@Mapper(componentModel = "spring")    
public abstract class SampleMapper {
        @Mappings({ 
            @Mapping(target = "id", source = "sno"),
            @Mapping(target = "name", source = "mNAme")
        })
        public abstract TargetDTO toDto(Source source);

        @IterableMapping(elementTargetType = String.class)
        protected abstract List<String> mapStringtoList(List<ChildSource> childSource);

        protected String mapChildSourceToString(ChildSource child) {
            return child.getAction();
        }
    }

但是我的动作列表在目标dto中设置为null。有人可以帮我吗？

Answer 1

您可以这样做。


@Mapper(componentModel = "spring")    
public abstract class SampleMapper {
        @Mappings({ 
            @Mapping(target = "id", source = "sno"),
            @Mapping(target = "name", source = "mNAme"),
            @Mapping(target = "actions", source = "childSource")
        })
        public abstract TargetDTO toDto(Source source);

        protected abstract List mapStringtoList(List childSource);

        protected String mapChildSourceToString(ChildSource child) {
            return child.getAction();
        }
    }

Answer 2

    @Mapper(componentModel = "spring")    
public abstract class SampleMapper {
        @Mappings({ 
            @Mapping(target = "id", source = "sno"),
            @Mapping(target = "name", source = "mNAme"),
            @Mapping(target = "actions", source = "childSource")
        })
        public abstract TargetDTO toDto(Source source);


        default String mapChildSourceToString(ChildSource child) {
            return child.getAction();
        }
}

使用mapstruct从List <object>映射List <string>

2 个答案: