Swift中的C结构表示

Question

在C中思考：我有内存缓冲区（平面3D），有数百万个~/.bash_profile结构，我想重新计算邻居：

Object

以后可以访问typedef struct Object { vector_int3 coords; struct Object *neighbours[6]; // Neighbouring objects in 6 directions int prop1; } Object;

我试图用Swift做同样的事情，我试过了：

chunk->neighbours[TOP]->prop1;

我只想在Swift中使用指向struct Object { var coords: vector_int3 // IMO this is wrong, because it allocates new heap buffer for 6 pointers var neighbours = UnsafeMutablePointer<Chunk>.allocate(capacity: 6) var prop1: Int ... } 的6个指针缓冲区，以便能够通过索引访问它。什么是最接近Swift实现提到的C结构？不，这不是过早的优化。

Answer 1

C结构的等价物看起来像

struct Object {
    var coords: vector_int3
    var neighbours: (UnsafeMutablePointer<Chunk>, UnsafeMutablePointer<Chunk>, UnsafeMutablePointer<Chunk>, UnsafeMutablePointer<Chunk>, UnsafeMutablePointer<Chunk>, UnsafeMutablePointer<Chunk>)
    var prop1: Int
    ...
}

是的，它非常笨拙。