Question

我坚持这个问题，并希望那里的任何人都可以帮助我。

我有一个包含以下行的配置文件：

config system interface
edit "internal1"
    set vdom "root"
    set ip 192.168.1.1 255.255.255.0
    set allowaccess ping https ssh http fgfm capwap
    set type physical
    set snmp-index 1
next
edit "internal2"
    set vdom "root"
    set ip 192.168.20.2 255.255.255.0
    set allowaccess ping https ssh http fgfm capwap
    set type physical
    set snmp-index 2
    Set secondary-IP enable
      config secondaryip
        edit 1
          set ip 192.168.21.2 255.255.255.0
        next
        edit 2
          set ip 192.168.22.2 255.255.255.0
        next
      end
next
edit "internal3"
    set vdom "root"
    set ip 192.168.30.3 255.255.255.0
    set allowaccess ping https ssh http fgfm capwap
    set type physical
    set snmp-index 3
    Set secondary-IP enable
      config secondaryip
        edit 1
          set ip 192.168.31.3 255.255.255.0
        next
      end
next
end
....

并希望匹配接口的名称，vdom，vlanid，ip和secondary-ip（s）以及以下正则表达式：

preg_match_all("/edit .+(\s+config secondaryip\r?\n(\s+edit \d+\r?\n.+\s+next\r?\n){1,}\s+end\r?\n)?.+next\r?\n/s", $configFile, $matched_interfaces);

第一个.+是所有匹配的而不是其他的！

任何建议的答案

Answer 1

我喜欢正则表达式

$regex = '/(?<=\vedit ")(\w+)|(?<=vdom ")(\w+)|(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\s\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(?=\s+set)|(\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\s\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(?=\s+next)/';
print_r(preg_match_all($regex, $configFile, $matched_interfaces));

输出

Array
(
[0] => Array
(
[0] => internal1
[1] => root
[2] => 192.168.1.1 255.255.255.0
[3] => internal2
[4] => root
[5] => 192.168.20.2 255.255.255.0
[6] => 192.168.21.2 255.255.255.0
[7] => 192.168.22.2 255.255.255.0
[8] => internal3
[9] => root
[10] => 192.168.30.3 255.255.255.0
[11] => 192.168.31.3 255.255.255.0
)

[1] => Array
(
[0] => internal1
[1] => 
[2] => 
[3] => internal2
[4] => 
[5] => 
[6] => 
[7] => 
[8] => internal3
[9] => 
[10] => 
[11] => 
)

[2] => Array
(
[0] => 
[1] => root
[2] => 
[3] => 
[4] => root
[5] => 
[6] => 
[7] => 
[8] => 
[9] => root
[10] => 
[11] => 
)

[3] => Array
(
[0] => 
[1] => 
[2] => 192.168.1.1 255.255.255.0
[3] => 
[4] => 
[5] => 192.168.20.2 255.255.255.0
[6] => 
[7] => 
[8] => 
[9] => 
[10] => 192.168.30.3 255.255.255.0
[11] => 
)

[4] => Array
(
[0] => 
[1] => 
[2] => 
[3] => 
[4] => 
[5] => 
[6] => 192.168.21.2 255.255.255.0
[7] => 192.168.22.2 255.255.255.0
[8] => 
[9] => 
[10] => 
[11] => 192.168.31.3 255.255.255.0
)

)

编辑以回答跟进

(?<=\vedit ")这是构造背后的正面看法，必须在括号中。此位?<=指定\v后面的正面外观与垂直空白相匹配，而edit "字面上匹配编辑＆＃34;。接下来是(\w+)，这意味着尽可能多地匹配单词字符，将其放在括号中会创建一个捕获组，以便稍后引用该匹配。背后的正面观察意味着(\w+)模式只有在它前面的序列背后的外观也匹配时才会匹配

您可以将组名添加到捕获组，以将它们作为命名数组返回

$regex = '/(?<=edit ")(?<name>\w+)\K|(?<=vdom ")(?<vdom>\w+)|(?<ip>\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\s\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(?=\s+set)|(?<secondary>\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3}\s\d{1,3}\.\d{1,3}\.\d{1,3}\.\d{1,3})(?=\s+next)\K/';

php preg_match_all多行模式

1 个答案: