文本替换后匹配子串的光标位置

时间:2017-10-05 18:39:18

标签: javascript string jquery-terminal

TL; DR

我有替换文本,字符串和光标位置(数字)的函数,我需要获取使用replace函数创建的新字符串的更正位置(数字),如果字符串更改的长度:

input and cursor position:  foo ba|r text
replacement: foo -> baz_text, bar -> quux_text
result: baz_text qu|ux_text text

input and cursor position:  foo bar| text
replacement: foo -> baz_text, bar -> quux_text
result: baz_text quux_text| text

input and cursor position:  foo bar| text
replacement: foo -> f, bar -> b
result: f b| text

input and cursor position:  foo b|ar text
replacement: foo -> f, bar -> b
result: f b| text

问题是我可以在原始文本上使用子字符串,但是替换将不匹配整个单词,因此需要对整个文本进行处理,但是子字符串将与替换匹配。

我对解决方案也很好,当原始光标位于替换单词的中间时,光标始终位于单词的末尾。

现在我的实现,在jQuery Terminal中我有一系列格式化函数:

$.terminal.defaults.formatters

他们接受一个字符串,它应该返回新的字符串,除了这种情况之外它工作正常:

当我有格式化程序改变长度时如果中断命令行,例如这个格式化程序:

$.terminal.defaults.formatters.push(function(string) {
   return string.replace(/:smile:/g, 'a')
                .replace(/(foo|bar|baz)/g, 'text_$1');
});

然后当命令行获取新字符串时光标位置错误。

我已经尝试解决这个问题,但它没有按预期工作,终端内部看起来像这样,

当我更改position时,我正在创建另一个变量formatted_position,该变量在命令行中用于显示光标。为了得到这个价值我用这个:

formatted_position = position;
var string = formatting(command);
var len = $.terminal.length(string);
var command_len = $.terminal.length(command);
if (len !== command_len) {
    var orig_sub = $.terminal.substring(command, 0, position);
    var orig_len = $.terminal.length(orig_sub);
    var formatted = formatting(orig_sub);
    var formatted_len = $.terminal.length(formatted);
    if (orig_len > formatted_len) {
        // if formatting make substring - (text before cursor)
        // shorter then subtract the difference
        formatted_position -= orig_len - formatted_len;
    } else if (orig_len < formatted_len) {
        // if the formatted string is longer add difference
        formatted_position += formatted_len - orig_len;
    }
}

if (formatted_position > len) {
    formatted_position = len;
} else if (formatted_position < 0) {
    formatted_position = 0;
}

$。terminal.substring和$ .terminal.length是终端格式识别的辅助函数(文本看起来像这个[[b;#fff;]hello])如果您要编写解决方案,您可以使用普通文本并使用字符串方法。< / p>

问题是当我将光标移动到已更改的单词的中间时

当文本较长时它会起作用,但对于较短的字符串,当文本位于被替换的单词的中间时,光标会向右跳转。

我尝试使用此代码修复此问题:

function find_diff(callback) {
    var start = position === 0 ? 0 : position - 1;
    for (var i = start; i < command_len; ++i) {
        var substr = $.terminal.substring(command, 0, i);
        var next_substr = $.terminal.substring(command, 0, i + 1);
        var formatted = formatting(next_substr);
        var substr_len = $.terminal.length(substr);
        var formatted_len = $.terminal.length(formatted);
        var diff = Math.abs(substr_len - formatted_len);
        if (diff > 1) {
            return diff;
        }
    }
    return 0;
}

...

} else if (len < command_len) {
    formatted_position -= find_diff();
} else if (len > command_len) {
    formatted_position += find_diff();
}

但是我认为这更糟糕的是因为当光标位于被替换的单词之前或之中时它会找到差异,并且只有当光标位于替换单词的中间时它才会找到diff。

您可以在此代码集https://codepen.io/jcubic/pen/qPVMPg?editors=0110中看到我尝试的结果(允许输入表情符号和foo bar baz替换为text_$1

更新

我已经使用这段代码了解它:

    // ---------------------------------------------------------------------
    // :: functions used to calculate position of cursor when formatting
    // :: change length of output text like with emoji demo
    // ---------------------------------------------------------------------
    function split(formatted, normal) {
        function longer(str) {
            return found && length(str) > length(found) || !found;
        }
        var formatted_len = $.terminal.length(formatted);
        var normal_len = $.terminal.length(normal);
        var found;
        for (var i = normal_len; i > 1; i--) {
            var test_normal = $.terminal.substring(normal, 0, i);
            var formatted_normal = formatting(test_normal);
            for (var j = formatted_len; j > 1; j--) {
                var test_formatted = $.terminal.substring(formatted, 0, j);
                if (test_formatted === formatted_normal &&
                    longer(test_normal)) {
                    found = test_normal;
                }
            }
        }
        return found || '';
    }
    // ---------------------------------------------------------------------
    // :: return index after next word that got replaced by formatting
    // :: and change length of text
    // ---------------------------------------------------------------------
    function index_after_formatting(position) {
        var start = position === 0 ? 0 : position - 1;
        var command_len = $.terminal.length(command);
        for (var i = start; i < command_len; ++i) {
            var substr = $.terminal.substring(command, 0, i);
            var next_substr = $.terminal.substring(command, 0, i + 1);
            var formatted_substr = formatting(substr);
            var formatted_next = formatting(next_substr);
            var substr_len = length(formatted_substr);
            var next_len = length(formatted_next);
            var test_diff = Math.abs(next_len - substr_len);
            if (test_diff > 1) {
                return i;
            }
        }
    }
    // ---------------------------------------------------------------------
    // :: main function that return corrected cursor position on display
    // :: if cursor is in the middle of the word that is shorter the before
    // :: applying formatting then the corrected position is after the word
    // :: so it stay in place when you move real cursor in the middle
    // :: of the word
    // ---------------------------------------------------------------------
    function get_formatted_position(position) {
        var formatted_position = position;
        var string = formatting(command);
        var len = $.terminal.length(string);
        var command_len = $.terminal.length(command);
        if (len !== command_len) {
            var orig_sub = $.terminal.substring(command, 0, position);
            var orig_len = $.terminal.length(orig_sub);
            var sub = formatting(orig_sub);
            var sub_len = $.terminal.length(sub);
            var diff = Math.abs(orig_len - sub_len);
            if (false && orig_len > sub_len) {
                formatted_position -= diff;
            } else if (false && orig_len < sub_len) {
                formatted_position += diff;
            } else {
                var index = index_after_formatting(position);
                var to_end = $.terminal.substring(command, 0, index + 1);
                //formatted_position -= length(to_end) - orig_len;
                formatted_position -= orig_len - sub_len;
                if (orig_sub && orig_sub !== to_end) {
                    var formatted_to_end = formatting(to_end);
                    var common = split(formatted_to_end, orig_sub);
                    var re = new RegExp('^' + $.terminal.escape_regex(common));
                    var to_end_rest = to_end.replace(re, '');
                    var to_end_rest_len = length(formatting(to_end_rest));
                    if (common orig_sub !== common) {
                        var commnon_len = length(formatting(common));
                        formatted_position = commnon_len + to_end_rest_len;
                    }
                }
            }
            if (formatted_position > len) {
                formatted_position = len;
            } else if (formatted_position < 0) {
                formatted_position = 0;
            }
        }
        return formatted_position;
    }

当您将表情符号键入为第一个字符并且光标位于以下位置时,它不适用于一种情况:smile:word。如何修复get_formatted_position函数以在替换后具有正确的固定位置?

更新:我问了不同的简单问题并使用了接受正则表达式和字符串的trackingReplace函数获得了解决方案,因此我将格式化程序的API更改为接受带有正则表达式和字符串的数组函数Correct substring position after replacement

1 个答案:

答案 0 :(得分:1)

所以我能够完成给定的任务,但是我无法将其实现到库中,因为我不确定如何在那里实现很多东西。

我在vanilla javascript中创建它,因此在实现到库时不应该有任何打嗝。该脚本主要依赖于textarea,输入或类似元素上可用的selectionStartselectionEnd属性。完成所有替换后,使用setSelectionRange方法将新选择设置为textarea。

// sel = [selectionStart, selectionEnd]
function updateSelection(sel, replaceStart, oldLength, newLength){
    var orig = sel.map(a => a)
    var diff = newLength - oldLength
    var replaceEnd = replaceStart + oldLength
    if(replaceEnd <= sel[0]){
        //  Replacement occurs before selection
        sel[0] += diff
        sel[1] += diff
        console.log('Replacement occurs before selection', orig, sel)
    }else if(replaceStart <= sel[0]){
        //  Replacement starts before selection
        if(replaceEnd >= sel[1]){
            //  and ends after selection
            sel[1] += diff
        }else{
            //  and ends in selection
        }
        console.log('Replacement starts before selection', orig, sel)
    }else if(replaceStart <= sel[1]){
        //  Replacement starts in selection
        if(replaceEnd < sel[1]){
            //  and ends in seledtion
        }else{
            //  and ends after selection
            sel[1] += diff
        }
        console.log('Replacement starts in selection', orig, sel)
    }
}

以下是整个演示:codepen

PS:根据我的观察,格式脚本经常运行。