Question

在我的应用程序中，我想使用服务来获取服务器请求我应该永远运行这项服务而不是阻止它！

我在服务中写下面的代码，但只显示5次，接收到5步。然后不显示Toast！

但我希望始终 getData() 并显示Toast 服务类：

public class NotifyService extends Service {

    private static final String TAG = "HelloService";
    private boolean isRunning = false;

    @Override
    public void onCreate() {
        Log.i(TAG, "Service onCreate");
        isRunning = true;
    }

    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {

        Log.i(TAG, "Service onStartCommand");
        //Creating new thread for my service
        //Always write your long running tasks in a separate thread, to avoid ANR
        new Thread(new Runnable() {
            @Override
            public void run() {

                //Your logic that service will perform will be placed here
                //In this example we are just looping and waits for 5000 milliseconds in each loop.
                for (int i = 0; i < 5; i++) {
                    try {
                        Thread.sleep(5000);
                    } catch (Exception e) {
                    }
                    if (isRunning) {
                        ExploreSendData sendData = new ExploreSendData();
                        sendData.setPageIndex(1);
                        sendData.setPageSize(10);
                        sendData.setShowFollows(false);
                        sendData.setShowMovies(true);
                        sendData.setShowNews(true);
                        sendData.setShowReplies(false);
                        sendData.setShowSeries(true);
                        sendData.setShowSuggestions(false);

                        InterfaceApi api = ApiClient.getClient().create(InterfaceApi.class);
                        Call<ExploreResponse> call = api.getExplore(new SharedPrefrencesHandler(NotifyService.this)
                                .getFromShared(SharedPrefrencesKeys.TOKEN.name()), sendData);

                        call.enqueue(new Callback<ExploreResponse>() {
                            @Override
                            public void onResponse(Call<ExploreResponse> call, Response<ExploreResponse> response) {
                                if (response.body().getData() != null && response.body().getStatusCode() != 401
                                        && response.body().getStatusCode() != 402) {

                                    Toast.makeText(NotifyService.this, "Test Show message ever 5second", Toast.LENGTH_SHORT).show();

                                }
                            }

                            @Override
                            public void onFailure(Call<ExploreResponse> call, Throwable t) {

                            }
                        });
                    }
                }
                //Stop service once it finishes its task
                stopSelf();
            }
        }).start();

        return Service.START_STICKY;
    }


    @Override
    public IBinder onBind(Intent arg0) {
        Log.i(TAG, "Service onBind");
        return null;
    }

    @Override
    public void onDestroy() {
        isRunning = false;
        Log.i(TAG, "Service onDestroy");
    }
}

我从互联网上复制这个服务代码，但只显示5次。 我希望show始终。

如何编辑我的代码并修复它？请帮我。感谢

Answer 1

问题不在于服务，服务启动和继续生活只要应用程序还活着并且android没有杀死它。对于无限循环，替换＆＃34; for循环＆＃34; with＆＃34; while loop＆＃34;。以下循环不会结束。

while (true) {
  ......
  ......
  ......
}

如何在Android中始终运行服务

1 个答案: