我有一组想要合并在一起的XML文件。主XML文档是完整的ISO 19139 XML文档,还有两个可能包含<gmd:descriptiveKeywords>
元素的XML文件。我需要从片段文件中提取任何这些<gmd:descriptiveKeywords>
元素并添加到主文件中。这些文件集有数百种,所以我需要进行一些匹配以确保我正在组合正确的数据集。
片段XML文件可能如下所示:
<?xml version="1.0" encoding="UTF-8"?>
<ValueSupplyChain xmlns:gmd="http://www.isotc211.org/2005/gmd"
xmlns:gco="http://www.isotc211.org/2005/gco" xmlns:gmx="http://www.isotc211.org/2005/gmx"
xmlns:xlink="http://www.w3.org/1999/xlink" id="MICA_B1v-101"
title="MINERALS4EU-EU MINERALS KNOWLEDGE DATA PLATFORM (EU-MKDP)">
<gmd:descriptiveKeywords>
<gmd:MD_Keywords id="exploration">
<gmd:keyword>
<gco:CharacterString>Exploration</gco:CharacterString>
</gmd:keyword>
<gmd:thesaurusName>
<gmd:CI_Citation>
<gmd:title>
<gco:CharacterString>MICA ontology
(ValueSupplyChainScheme)</gco:CharacterString>
</gmd:title>
<gmd:date gco:nilReason="unknown"/>
<gmd:edition>
<gco:CharacterString>2</gco:CharacterString>
</gmd:edition>
<gmd:identifier>
<gmd:MD_Identifier>
<gmd:code>
<gmx:Anchor
xlink:href="https://w3id.org/mica/ontology/MicaOntology/7418a9ae1cd44847889c2c92408e1e71"
/>
</gmd:code>
</gmd:MD_Identifier>
</gmd:identifier>
</gmd:CI_Citation>
</gmd:thesaurusName>
</gmd:MD_Keywords>
</gmd:descriptiveKeywords>
</ValueSupplyChain>
主XML具有如下结构(使用图像,因为XML可以变得非常大):
理想情况下,我想在现有关键字部分下方附加相关的片段部分,并创建一个新的主文档。
我的问题是,虽然我似乎能够匹配正确的数据集,并找到相关的部分,但我认为我认为我永远不会写入输出目标文件。< / p>
我的代码是:
import logging
import platform
import glob
import os
from lxml import etree as et
logging.getLogger().setLevel(logging.DEBUG)
PC_name = platform.node()
if PC_name == 'blah ':
root_directory = "blah\\blah\\outputs\\"
dir_sep = "\\"
else:
root_directory = "C:\\Temp\\"
dir_sep = "\\"
batch_directory_name = "Batch1"
batch_number = "1"
in_directory = root_directory + batch_directory_name
out_directory_name = "splodge"
out_directory = in_directory + dir_sep + out_directory_name
if not os.path.exists(out_directory):
os.makedirs(out_directory)
os.chdir(in_directory)
fileSuffix = ".xml"
globDirSep = "/"
fileTStem = "T" + batch_number + "_"
fileDStem = "D" + batch_number + "_"
fileVStem = "V" + batch_number + "_"
fileTPattern = fileTStem + "[0-9]*" + fileSuffix
globTPattern = in_directory + globDirSep + fileTPattern
stem = in_directory + dir_sep + fileTStem
ns_all = {'gmd': 'http://www.isotc211.org/2005/gmd',
'gco': 'http://www.isotc211.org/2005/gco',
'gmx': 'http://www.isotc211.org/2005/gmx',
'xsi': 'http://www.w3.org/2001/XMLSchema-instance',
'gml': 'http://www.opengis.net/gml',
'xlink': 'http://www.w3.org/1999/xlink',
'geonet': 'http://www.fao.org/geonetwork'}
record_title = \
'gmd:identificationInfo/gmd:MD_DataIdentification/gmd:citation/gmd:CI_Citation/gmd:title/gco:CharacterString'
record_keywords = 'gmd:identificationInfo/gmd:MD_DataIdentification/gmd:descriptiveKeywords'
for file in glob.glob(globTPattern):
'Get the record number of the current T file'
fnum = file.replace(stem, "").replace(fileSuffix, "")
tree = et.parse(file)
root = tree.getroot()
recordT = root.find(record_title, ns_all)
'We want to use the UPPER case version to compare with D and V file titles'
RecordTitle = recordT.text.upper()
logging.debug("T title: " + RecordTitle)
dFile = in_directory + dir_sep + fileDStem + fnum + fileSuffix
vFile = in_directory + dir_sep + fileVStem + fnum + fileSuffix
'Find keyword sections in T file (and how many for interest...)'
keywordList = root.findall(record_keywords, ns_all)
knum = len(keywordList)
logging.debug("T file has the following number of gmd:descriptiveKeywords sections: " + str(knum))
try:
dTree = et.parse(dFile)
dRoot = dTree.getroot()
recordDT = dRoot.attrib['title']
logging.debug("D title: " + recordDT)
if RecordTitle == recordDT:
logging.debug("T and D titles are the same, we can continue...")
'If the titles match then we can insert the D keywords fragment'
DKeywords = dRoot.findall('gmd:descriptiveKeywords', ns_all)
dnum = len(DKeywords)
logging.debug("D file has the following number of gmd:descriptiveKeywords sections: " + str(dnum))
keywordList.extend(DKeywords)
logging.debug("Subtotal: " + str(len(keywordList)))
else:
logging.debug("T and D titles don't match")
except:
logging.debug("Cannot parse: " + dFile)
try:
vTree = et.parse(vFile)
vRoot = vTree.getroot()
recordVT = vRoot.attrib['title']
logging.debug("V title: " + recordVT)
if RecordTitle == recordVT:
logging.debug("T and V titles are the same, we can continue...")
'If the titles match then we can insert the V keywords fragment'
VKeywords = vRoot.findall('gmd:descriptiveKeywords', ns_all)
vnum = len(VKeywords)
logging.debug("V file has the following number of gmd:descriptiveKeywords sections: " + str(vnum))
keywordList.extend(VKeywords)
logging.debug("Subtotal: " + str(len(keywordList)))
else:
logging.debug("T and V titles don't match")
except:
logging.debug("Cannot parse: " + vFile)
newFile = "out" + batch_number + "_" + fnum + fileSuffix
writeTo = out_directory_name + dir_sep + newFile
tree.write(writeTo)
,调试输出如下:
DEBUG:root:T title: BGR BOREHOLE MAP
DEBUG:root:T file has the following number of gmd:descriptiveKeywords sections: 7
DEBUG:root:D title: BGR BOREHOLE MAP
DEBUG:root:T and D titles are the same, we can continue...
DEBUG:root:D file has the following number of gmd:descriptiveKeywords sections: 5
DEBUG:root:Subtotal: 12
DEBUG:root:V title: BGR BOREHOLE MAP
DEBUG:root:T and V titles are the same, we can continue...
DEBUG:root:V file has the following number of gmd:descriptiveKeywords sections: 1
DEBUG:root:Subtotal: 13
DEBUG:root:T title: 3D, 4D AND PREDICTIVE MODELLING OF MAJOR MINERAL BELTS IN EUROPE
DEBUG:root:T file has the following number of gmd:descriptiveKeywords sections: 36
DEBUG:root:D title: 3D, 4D AND PREDICTIVE MODELLING OF MAJOR MINERAL BELTS IN EUROPE
DEBUG:root:T and D titles are the same, we can continue...
DEBUG:root:D file has the following number of gmd:descriptiveKeywords sections: 5
DEBUG:root:Subtotal: 41
从调试信息看,我成功添加到gmd:descriptiveKeywords元素,列表长度按预期增加,但正如我所说,当我写出XML时,我得到原始主的内容文件。
我也尝试使用ElementTree,但我遇到了同样的问题;此外,输出不支持主服务器中使用的名称空间前缀。
我做错了什么?
修改
重现问题的最小代码如下:
from lxml import etree as et
# Open the master file, which is a well-formed and schema valid ISO 19139 XML record
tree = et.parse('T1_0.xml')
root = tree.getroot()
ns_all = {'gmd': 'http://www.isotc211.org/2005/gmd',
'gco': 'http://www.isotc211.org/2005/gco',
'gmx': 'http://www.isotc211.org/2005/gmx',
'xsi': 'http://www.w3.org/2001/XMLSchema-instance',
'gml': 'http://www.opengis.net/gml',
'xlink': 'http://www.w3.org/1999/xlink',
'geonet': 'http://www.fao.org/geonetwork'}
keywordList = root.findall('gmd:identificationInfo/gmd:MD_DataIdentification/gmd:descriptiveKeywords', ns_all)
# Just a quick check that everything works as expected
print(len(keywordList)) # Should return 7 for the master file
# Open a well-formed XML file containing content we wish to add to the (or a copy of the) master record
dTree = et.parse('D1_0.xml')
dRoot = dTree.getroot()
DKeywords = dRoot.findall('gmd:descriptiveKeywords', ns_all)
# Just a quick check that everything works as expected
print(len(DKeywords)) # Should return 5 for the D file
# Add the keywords from the second file to the keywords of the master file
keywordList.extend(DKeywords)
# We've added 5 records so the result should be 12
print(len(keywordList)) # I get 12 here
# Write out the new file
tree.write('combinedTD1_0.xml')
# If all worked as expected the new file should have 12
ctree = et.parse('combinedTD1_0.xml')
croot = ctree.getroot()
CKeywords = croot.findall('gmd:identificationInfo/gmd:MD_DataIdentification/gmd:descriptiveKeywords', ns_all)
print(len(CKeywords)) # I get 7 :(
文件是:
主文件示例:T1_0.xml
片段文件示例:D1_0.xml
片段文件示例:V1_0.xml
答案 0 :(得分:1)
keywordList.extend(DKeywords)
只是将元素添加到列表中。此操作对XML树没有任何作用。
要将其他descriptiveKeywords
节点插入主文档中的节点的兄弟节点,您可以执行以下操作:
# Get the last of the descriptiveKeywords nodes in the master document
last_kw = keywordList[-1]
# Get the node's parent and its position (index) within the parent
kw_parent = last_kw.getparent()
ix = kw_parent.index(last_kw)
# Insert the descriptiveKeyword nodes from the fragment file as successive siblings
for dk in DKeywords:
kw_parent.insert(ix+1, dk)
ix += 1
答案 1 :(得分:1)
正如我多次回答的那样,在需要操作XML文件(如合并文档)时,请考虑XSLT这种用于转换XML文件的专用语言。 Python的lxml
模块可以运行XSLT 1.0脚本。
具体来说,XSLT维护document()
函数,您可以传递文件名参数以将片段节点附加到现有主节点。此外,XSLT使用Identity Transform复制整个文档,使用Muenchian Grouping按不同的关键字索引文档。使用这种方法,所需的唯一for
循环是迭代文件。
由于OP未设置可重现的示例,下面是使用StackOverflow在python和xslt标记中排名前3位的用户的示例演示。主文件以前1名开头。然后Python脚本迭代以追加第二等级,然后按<tag1>
追加第三等级:
掌握XML (排名前1位的用户)
<?xml version="1.0"?>
<stackoverflow>
<group lang="python">
<topusers>
<user>Martijn Pieters</user>
<link>https://stackoverflow.com/users/100297/martijn-pieters</link>
<location>Cambridge, United Kingdom </location>
<year_rep>70,404</year_rep>
<total_rep>590,309</total_rep>
<tag1>python</tag1>
<tag2>python-3.x</tag2>
<tag3>python-2.7</tag3>
</topusers>
</group>
<group lang="xslt">
<topusers>
<user>Dimitre Novatchev</user>
<link>https://stackoverflow.com/users/36305/dimitre-novatchev</link>
<location>United States</location>
<year_rep>9,922</year_rep>
<total_rep>197,245</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xpath</tag3>
</topusers>
</group>
</stackoverflow>
Rank 2 XML (即片段)
<?xml version="1.0" encoding="utf-8"?>
<stackoverflow>
<group lang="python">
<topusers>
<user>Alex Martelli</user>
<link>https://stackoverflow.com/users/95810/alex-martelli</link>
<location>Sunnyvale, CA</location>
<year_rep>49,172</year_rep>
<total_rep>540,372</total_rep>
<tag1>python</tag1>
<tag2>list</tag2>
<tag3>c++</tag3>
</topusers>
</group>
<group lang="python">
<topusers>
<user>Martin Honnen</user>
<link>https://stackoverflow.com/users/252228/martin-honnen</link>
<location>Germany</location>
<year_rep>10,046</year_rep>
<total_rep>92,604</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xpath</tag3>
</topusers>
</group>
</stackoverflow>
Rank 3 XML (即片段)
<?xml version="1.0" encoding="utf-8"?>
<stackoverflow>
<group lang="python">
<topusers>
<user>unutbu</user>
<link>https://stackoverflow.com/users/190597/unutbu</link>
<location></location>
<year_rep>55,492</year_rep>
<total_rep>453,267</total_rep>
<tag1>python</tag1>
<tag2>pandas</tag2>
<tag3>numpy</tag3>
</topusers>
</group>
<group lang="xslt">
<topusers>
<user>michael.hor257k</user>
<link>https://stackoverflow.com/users/3016153/michael-hor257k</link>
<location></location>
<year_rep>11,339</year_rep>
<total_rep>70,473</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xslt-1.0</tag3>
</topusers>
</group>
</stackoverflow>
XSLT (将.xsl文件另存为.xml文件保存在同一目录中)
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output indent="yes" omit_xml_declaration="no"/>
<xsl:strip-space elements="*"/>
<xsl:key name="keyid" match="topusers" use="tag1" />
<xsl:param name="fragment" />
<!-- IDENTITY TRANSFORM -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<!-- IMPORT XML FRAGMENT -->
<xsl:template match="group">
<xsl:copy>
<xsl:copy-of select="@*"/>
<xsl:apply-templates select="topusers[generate-id() = generate-id(key('keyid', tag1))]"/>
</xsl:copy>
</xsl:template>
<!-- COPY EXISTING topusers AND APPEND EXTERNAL topusers BY SAME KEYWORD -->
<xsl:template match="topusers">
<xsl:variable select="tag1" name="keyword"/>
<xsl:for-each select="key('keyid', tag1)">
<xsl:copy-of select="."/>
</xsl:for-each>
<!-- PASS PYTHON PARAM INTO document() -->
<xsl:copy-of select="document($fragment)/stackoverflow/group/topusers[tag1=$keyword]"/>
</xsl:template>
</xsl:stylesheet>
Python (解析所有xml和xsl文件)
import os
import lxml.etree as et
# CURRENT DIRECTORY OF SCRIPT
cd = os.path.dirname(os.path.abspath(__file__))
master = os.path.join(cd, 'Master.xml')
# LOAD XSL SCRIPT
xsl = et.parse(os.path.join(cd, 'XSLTScript.xsl'))
transform = et.XSLT(xsl)
# ITERATE THROUGH FRAGMENT XML FILES IN DIRECTORY
for f in sorted(os.listdir(cd)):
if f.endswith('.xml'):
# LOAD MASTER XML
doc = et.parse(master)
print(f)
# PASS FILE NAME AS PARAMETER FOR XSLT's document()
n = et.XSLT.strparam(f)
result = transform(doc, fragment=n)
# UPDATE MASTER XML
with open(master, 'wb') as s:
s.write(result)
输出 (每个标记排名前3位)
<?xml version="1.0"?>
<stackoverflow>
<group lang="python">
<topusers>
<user>Martijn Pieters</user>
<link>https://stackoverflow.com/users/100297/martijn-pieters</link>
<location>Cambridge, United Kingdom </location>
<year_rep>70,404</year_rep>
<total_rep>590,309</total_rep>
<tag1>python</tag1>
<tag2>python-3.x</tag2>
<tag3>python-2.7</tag3>
</topusers>
<topusers>
<user>Alex Martelli</user>
<link>https://stackoverflow.com/users/95810/alex-martelli</link>
<location>Sunnyvale, CA</location>
<year_rep>49,172</year_rep>
<total_rep>540,372</total_rep>
<tag1>python</tag1>
<tag2>list</tag2>
<tag3>c++</tag3>
</topusers>
<topusers>
<user>unutbu</user>
<link>https://stackoverflow.com/users/190597/unutbu</link>
<location/>
<year_rep>55,492</year_rep>
<total_rep>453,267</total_rep>
<tag1>python</tag1>
<tag2>pandas</tag2>
<tag3>numpy</tag3>
</topusers>
</group>
<group lang="xslt">
<topusers>
<user>Dimitre Novatchev</user>
<link>https://stackoverflow.com/users/36305/dimitre-novatchev</link>
<location>United States</location>
<year_rep>9,922</year_rep>
<total_rep>197,245</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xpath</tag3>
</topusers>
<topusers>
<user>Martin Honnen</user>
<link>https://stackoverflow.com/users/252228/martin-honnen</link>
<location>Germany</location>
<year_rep>10,046</year_rep>
<total_rep>92,604</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xpath</tag3>
</topusers>
<topusers>
<user>michael.hor257k</user>
<link>https://stackoverflow.com/users/3016153/michael-hor257k</link>
<location/>
<year_rep>11,339</year_rep>
<total_rep>70,473</total_rep>
<tag1>xslt</tag1>
<tag2>xml</tag2>
<tag3>xslt-1.0</tag3>
</topusers>
</group>
</stackoverflow>
OP XSLT
适合OP的实际主文件和片段文件的相应XSLT可能看起来像这个未经测试的版本。下面假设关键字与发布的fragement处于相同的布局(由于图像关闭了<gmd:descriptiveKeywords>
节点,因此无法判断):
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:gmd="http://www.isotc211.org/2005/gmd"
xmlns:gco="http://www.isotc211.org/2005/gco"
xmlns:gmx="http://www.isotc211.org/2005/gmx"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:gml="http://www.opengis.net/gml"
xmlns:xlink="http://www.w3.org/1999/xlink"
xmlns:geonet="http://www.fao.org/geonetwork">
<xsl:output indent="yes" omit_xml_declaration="no"/>
<xsl:strip-space elements="*"/>
<xsl:key name="keyid" match="gmd:MD_Keywords" use="gmd:keyword/gco:CharacterString" />
<xsl:param name="fragment" />
<!-- IDENTITY TRANSFORM -->
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<!-- IMPORT XML FRAGMENT -->
<xsl:template match="gmd:descriptiveKeywords">
<xsl:copy>
<xsl:apply-templates select="gmd:MD_Keywords[generate-id() = generate-id(key('keyid', gmd:keyword/gco:CharacterString))]"/>
</xsl:copy>
</xsl:template>
<!-- COPY EXISTING gmd:MD_Keywords AND APPEND EXTERNAL gmd:MD_Keywords BY SAME KEYWORD -->
<xsl:template match="gmd:MD_Keywords">
<xsl:variable select="gmd:keyword/gco:CharacterString" name="keyword"/>
<xsl:for-each select="key('keyid', gmd:keyword/gco:CharacterString)">
<xsl:copy-of select="."/>
</xsl:for-each>
<!-- PASS PYTHON PARAM INTO document() -->
<xsl:copy-of select="document($fragment)/ValueSupplyChain/gmd:descriptiveKeywords/gmd:MD_Keywords[gmd:keyword/gco:CharacterString=$keyword]"/>
</xsl:template>
</xsl:stylesheet>