Question

我有一个基本上保存地址的数据库

表（tblAddress）看起来像这样......

housename    | housenumber | address1    | address2        | address3 | town      | postcode
Banana House |          29 | Acacia Road | Yellow Skin Way |          | Nuttytown | W1 1MP

当我根据邮政编码搜索数据库时，我希望能够返回并得到这样的结果......

Banana House,29 Acacia Road,Yellow Skin Way,Nuttytown,W1 1MP

所以我需要与address1连接的housenumber填充IF地址1。如果没有，那么与address2或address3连接。然后根据示例遵循地址的其余部分。

我尝试过使用IF和CASE语句，但似乎无法接近输出后的任何位置。

希望这是有道理的。

Answer 1

你可以通过增加几个连接操作来实现。

检查以下代码是否有效。

SELECT CONCAT(housename, CONCAT(" ",CONCAT(housenumber, CONCAT(" ",CONCAT_WS(' ,', 
                  NULLIF(address1, ''), 
                  NULLIF(address2, ''), 
                  NULLIF(address3, ''),
                  NULLIF(town, ''),
                  NULLIF(postcode, '')))))) AS concatedAddress FROM tblAddress;

Answer 2

使用concat_ws()（与分隔符连接）以及nullif()

SELECT CONCAT_WS(',', NULLIF(housename, ''), 
                      NULLIF(housenumber, ''),  
                      NULLIF(address1, ''), 
                      NULLIF(address2, ''), 
                      NULLIF(address3, ''),
                      NULLIF(town, ''),
                      NULLIF(postcode, '')
       ) AS address FROM tblAddress

Answer 3

尝试如下，

 SELECT CONCAT_WS ( ", ",
    housename,
    CONCAT(housenumber, CONCAT_WS (", ", NULLIF(address1, ''), NULLIF(address2, ''), NULLIF(address3, ''))),
    town,
    postcode) AS address
FROM tblAddress

Answer 4

这个怎么样：

SELECT 
       housename
      ,CONCAT( housenumber, CONCAT(' ', COALESCE(address1, '')), CONCAT(' ', COALESCE(address2, '')), CONCAT(' ', COALESCE(address3, '')) ) AS address
      ,town
      ,postcode 
FROM tblAddress;

MySQL SELECT条件CONCAT

4 个答案: