Question

我必须通过网站上的搜索查询搜索CVE或常见漏洞和曝光，然后在我的打印请求中打印导入的结果表。我用来抓取结果的网站是https://cve.mitre.org/cgi-bin/cvekey.cgi?keyword=CVE+2017

我正在使用python 3进行编码并且是新手，并希望将其用作项目

import urllib.request
import urllib
searchStr = input("Enter Search Query \n")
r = urllib.request.urlopen("https://cve.mitre.org/cgi-bin/cvekey.cgi?
keyword="+searchStr)
source_code = r.read()
from bs4 import BeautifulSoup
soup = BeautifulSoup(source_code, 'html.parser')
table = soup.find('tbody', id = 'TableWithRules')
rows = table.find('tr')
for tr in rows:
    cols = tr.find('td')
    p = cols[0].text.strip()
    d = cols[1].text.strip
    print(p)
    print(d)

给我以下错误：

Traceback (most recent call last):
  File "C:\Users\Devanshu Misra\Desktop\Python\CVE_Search.py", line 9, in 
<module>
    rows = table.find('tr')
AttributeError: 'NoneType' object has no attribute 'find'

Answer 1

import urllib.request
searchStr = input("Enter Search Query \n")
r = urllib.request.urlopen("https://cve.mitre.org/cgi-bin/cvekey.cgi?
keyword="+searchStr)
source_code = r.read()
from bs4 import BeautifulSoup
soup = BeautifulSoup(source_code, 'html.parser')

# FIRST OF ALL SEE THAT THE ID "TableWithRules" is associated to the divtag 

table = soup.find('div', {"id" : 'TableWithRules'})
rows=table.find_all("tr")   # here you have to use find_all for finding all rows of table
for tr in rows:
    cols = tr.find_all('td') #here also you have to use find_all for finding all columns of current row
    if cols==[]: # This is a sanity check if columns are empty it will jump to next row
        continue
    p = cols[0].text.strip()
    d = cols[1].text.strip()
    print(p)
    print(d)

Answer 2

“正确”的答案不正确
这行是错误的：

divtag=soup.find('div',{'id':'TableWithRules'})

应该是：

table=soup.find('div',{'id':'TableWithRules'})

AttributeError：'NoneType'对象没有属性'find'

2 个答案: