我试图检查一系列单元格是否都有另一个范围内定义的值
这是我目前的代码:
Sub CheckInstallationName()
Dim LastRow As Long
With Worksheets(2)
LastRow = .Cells(.Rows.Count, Worksheets(1).Cells(4, 3).Value).End(xlUp).Row
End With
Dim rngA As Range
Set rngA = Range(Worksheets(1).Cells(4, 3).Value & "4:" & Worksheets(1).Cells(4, 3).Value & LastRow)
Dim cellA As Range
Dim InstallationNameRange As Variant
InstallationNameRange = Worksheets(1).Range("B16:B32").Value
For Each cellA In rngA
If UBound(Filter(InstallationNameRange, cellA.Value)) < 0 Then
'Some code
End If
Next cellA
End Sub
在If UBound(filter(InstallationNameRange, cellA.Value)) < 0 Then
我收到错误“运行时错误'13':输入不匹配”,但无法找到解决方法。可能这是一个非常小的修复。没有这个if语句,代码就可以了
答案 0 :(得分:1)
打开一个新的Excel并编写以下内容:
Public Sub CheckRangeInRange()
Dim rngA As Range
Dim rngB As Range
Dim rngCellA As Range
Dim rngCellB As Range
Dim blnError As Boolean
Set rngA = Worksheets(1).Range("A1:B10")
Set rngB = Worksheets(1).Range("D10:E20")
rngA.Interior.Color = vbYellow
rngB.Interior.Color = vbRed
For Each rngCellA In rngA
blnError = True
For Each rngCellB In rngB
If rngCellA = rngCellB Then
blnError = False
End If
Next rngCellB
If blnError Then Debug.Print "Display Error here!"
Next rngCellA
End Sub
在A1:B10
和D10:E20
中添加一些值,匹配值的地址将在即时窗口中打印。
答案 1 :(得分:1)
您不能在2-d范围内使用Filter
,并且从Range
创建的任何数组都是2-d,即使它是单行或列也是如此。
您可以按照question使用'double Transpose
技巧。请注意高度投票的答案,而不是被接受的答案。
E.g:
Option Explicit
Sub Test()
Dim rng As Range
Set rng = Sheet2.Range("C20:E20") 'a, b, c
' use the double transpose trick to convert 2-d array to 1-d array
Dim arr As Variant
arr = Application.WorksheetFunction.Transpose( _
Application.WorksheetFunction.Transpose(rng.Value))
' now Filter will work
Dim out As Variant
out = Filter(arr, "a")
Debug.Print out(0)
End Sub