Django Python str()参数2必须是str,而不是int

时间:2017-10-04 22:32:26

标签: python django

我有一个带有值的12x12字典,对所有人都是0。

matchfield = {}
    for i in range(12):
        for j in range(12):
            matchfield[str((i, j))] = 0

我想使用以下代码段将一些值设置为1(它会检查周围的字段是否空闲):

length = 4
m = randint(1, 10-length)
n = randint(1, 10)
for x in range(m-1, m+length+1):
    for y in range(n-1, n+1):
        if not matchfield[str((x, y))]:
            for k in range(length):
                matchfield[str((m+k, n))] = 1

如果我在python控制台中测试它,所有工作和4个选定值都设置为1,但在我的Django视图函数中,我在下一行得到了一个TypeError:

matchfield [str((m + k,n))] = 1

Environment:


Request Method: GET
Request URL: https://www.maik-kusmat.de/schiffeversenken/start/

Django Version: 1.11.5
Python Version: 3.5.3
Installed Applications:
['django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'django.contrib.sites',
 'django.contrib.flatpages',
 'accounts',
 'home',
 'contact',
 'kopfrechnen',
 'braces',
 'ckeditor',
 'ckeditor_uploader',
 'battleship',
 'hangman']
Installed Middleware:
['django.middleware.security.SecurityMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware',
 'django.middleware.locale.LocaleMiddleware',
 'django.contrib.flatpages.middleware.FlatpageFallbackMiddleware']



Traceback:

File "/home/pi/Dev/mkenergy/lib/python3.5/site-packages/django/core/handlers/exception.py" in inner
  41.             response = get_response(request)

File "/home/pi/Dev/mkenergy/lib/python3.5/site-packages/django/core/handlers/base.py" in _get_response
  187.                 response = self.process_exception_by_middleware(e, request)

File "/home/pi/Dev/mkenergy/lib/python3.5/site-packages/django/core/handlers/base.py" in _get_response
  185.                 response = wrapped_callback(request, *callback_args, **callback_kwargs)

File "/home/pi/Dev/mkenergy/lib/python3.5/site-packages/django/contrib/auth/decorators.py" in _wrapped_view
  23.                 return view_func(request, *args, **kwargs)

File "/home/pi/Dev/mkenergy/src/battleship/views.py" in battleship_start
  36.                                 matchfield[str((m+k, n))] = 1

Exception Type: TypeError at /schiffeversenken/start/
Exception Value: str() argument 2 must be str, not int
我错过了什么吗?我不明白错误

1 个答案:

答案 0 :(得分:1)

如果您有

,我希望会出现argument 2 must be str错误
matchfield[str(m+k, n)]

在Python 3中,str的第二个参数是编码,因此整数n会导致该错误。

但是,您的追溯会显示matchfield[str((m+k, n))],这不应该导致该错误。尝试重新启动Django服务器以确保您正在运行当前代码。

首先,我建议您使用元组作为字典键,例如

matchfield[(i, j)] = 0

但是,如果您要将matchfield序列化为json,那么因为键必须是字符串而无法正常工作。