如何在视图失去焦点时屏蔽EditText中的文本。

时间:2017-10-04 21:52:03

标签: android android-edittext

因此,如果用户输入“1234”,他们将在EditText字段中看到“1234”。但是当那个领域失去焦点时,我希望它显示“****”

所以我实现了一个自定义TransformationMethod,如果EditText字段没有焦点,它只会屏蔽输入的文本。

当我输入文本“12345”时,它显示为“12345”,但是当我点击不同的字段时,数字永远不会被屏蔽。我想看“*****”,但我仍然看到相同的“12345”

如果我旋转设备(强制它重新加载所有东西),它会正确显示“*****”。当我点击EditText字段时,它会正确地将屏蔽文本从“*****”更改为“12345”因此,在获得焦点时它会起作用,但在失去焦点时则不起作用。我试过实现一个OnFocusChangeListener,但似乎没有任何影响。

有什么办法可以强制EditText字段在失去焦点时重绘文字?

设定:

 editText.setTransformationMethod(CustomPasswordTransformationMethod(numUnobfuscatedDigits))
editText.setOnFocusChangeListener { view, hasFocus ->
                    ((EditText)view).invalidate()    
                     ((EditText)view).refreshDrawableState()                    

CustomPasswordTransformationMethod:     public class CustomPasswordTransformationMethod extends PasswordTransformationMethod {         private int unObfuscated = 1;         private boolean mIsFocused = false;

    /**
     * @param number the number of digits that will be unObfuscated at the end of the input string. Must be a positive integer or 0.
     */
    public CustomPasswordTransformationMethod(int number) {
        if (number < 0) {
            Log.e(TAG, "Invalid parameter number =" + number + " number of un-obfuscated digits must be a positive integer or 0.");
            unObfuscated = 0;
        }
        unObfuscated = number;
    }

    @Override
    public CharSequence getTransformation(CharSequence source, View view) {
        return new PasswordCharSequence(source);
    }

    @Override
    public void onFocusChanged(View view, CharSequence sourceText,
                               boolean focused, int direction,
                               Rect previouslyFocusedRect) {
        super.onFocusChanged(view,sourceText,focused, direction, previouslyFocusedRect);
        mIsFocused = focused;
    }


    private class PasswordCharSequence implements CharSequence {
        private CharSequence mSource;

        public PasswordCharSequence(CharSequence source) {
            mSource = source; // Store char sequence
        }

        public char charAt(int index) {
            if(mIsFocused) return mSource.charAt(index);
            else {
                if (index < ((length()) - unObfuscated)) return '●';
                return mSource.charAt(index);
            }
        }

        public int length() {
            return mSource.length(); // Return default
        }

        public CharSequence subSequence(int start, int end) {
            return mSource.subSequence(start, end); // Return default
        }
    }
};

2 个答案:

答案 0 :(得分:1)

试试这个,看看它是否能满足您的需求。

editText.setOnFocusChangeListener(new View.OnFocusChangeListener() {
    @Override
    public void onFocusChange(View view, boolean hasFocus) {
        if(hasFocus){
            editText.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
        }
        else{
            editText.setTransformationMethod(PasswordTransformationMethod.getInstance());
        }
    }
});

答案 1 :(得分:0)

也许你可以尝试保持简单:

String password = "";

editText.setOnFocusChangeListener(new OnFocusChangeListener() {
    @Override
    public void onFocusChange(View view, boolean hasFocus) {
        if (hasFocus) {
            editText.setText(password, TextView.BufferType.EDITABLE);
        } else {
            password = editText.getText().toString();
            String ofuscated = "";
            for (int i = 0; i < password.length(); i++){ ofuscated += "*"; }
            editText.setText(ofuscated, TextView.BufferType.EDITABLE);
        }
    }
});