Question

这是mytable中的数据：

select Name, LastName, Id, LocationId, Date, Time, RN from mytable


Name    LastName    Id  LocationId  Date        Time        RN
Office  Jones       284 NY          20171004    1540        1
Office  Jones       284 NY          20171004    1545        2
Office  Jones       284 NY          20171004    1550        3

Office  Jones       284 NY          20171004    1650        4

Office  Jones       284 NY          20171113    1030        1
Office  Jones       284 NY          20171113    1035        2
Office  Jones       284 NY          20171113    1040        3

Office  Jones       284 NY          20171113    1130        4
Office  Jones       284 NY          20171113    1135        5
Office  Jones       284 NY          20171113    1140        6

Office  Jones       284 NY          20171113    1230        7
Office  Jones       284 NY          20171113    1435        8
Office  Jones       284 NY          20171113    1740        9

Office  Jones       284 NY          20171113    1840        10

Office  Jones       284 NY          20171115    1030        1
Office  Jones       284 NY          20171115    1035        2
Office  Jones       284 NY          20171115    1040        3

我想根据按日期分组的3个连续行显示我的结果名称，姓氏，姓名，位置ID，日期，分钟（时间）

Name    LastName    Id  LocationId  Date        Time
Office  Jones       284 NY          20171004    1540
Office  Jones       284 NY          20171113    1030
Office  Jones       284 NY          20171113    1130
Office  Jones       284 NY          20171113    1230
Office  Jones       284 NY          20171115    1030

这是我到目前为止所做的，但我无法弄清楚如何将其他2行纳入我的结果

SELECT  Name,   LastName,   Id, LocationId, Date,  min(Time) as Time FROM mytable
WHERE Date IN (SELECT Date
                       FROM mytable
                      WHERE RN = 3)
GROUP BY Name,  LastName,   Id, LocationId, Date



Name    LastName    Id  LocationId  Date        Time
Office  Jones       284 NY          20171004    1540
Office  Jones       284 NY          20171113    1030
Office  Jones       284 NY          20171115    1030

Answer 1

如何在rn上使用算术？

select name, lastname, id, locationid, date, min(time)
from t
group by name, lastname, id, locationid,
         (rn - 1) / 3;

或者只有一个where：

select name, lastname, id, locationid, date, time
from t
where rn % 3 = 1;

Answer 2

这是一个简化版本，删除常量值列，只关注计算所需的列（我将其转储到临时表中）。内连接中的派生表确定最大行数，每个日期是三的倍数，并且三个结果的聚类在外部查询的分组上：

select #tmp.dates,
       min(#tmp.times)
from #tmp
inner join (select dates,
                   max(rnum) rnum_x
            from #tmp
            where rnum % 3 = 0 
            group by dates ) x
    on #tmp.dates = x.dates
   and #tmp.rnum <= x.rnum_x
group by #tmp.dates,
       case when rnum%3 = 0
                then rnum/3 - 1
       else rnum/3
       end

如何根据按日期分组的3个连续行选择最小值（时间）

2 个答案: