Question

我在Windows上的Visual Studio中编写了一个程序，程序编译正确，但没有向控制台显示所需的输出。但是，如果我在Linux上编译并运行Gedit中的程序，则显示正确的输出并且一切正常。为什么是这样？代码如下：

#include <iostream>
#include <fstream>

using namespace std;

int main()
{
string input;

cout << "College Admission Generator\n\n";

cout << "To begin, enter the location of the input file (e.g. C:\\yourfile.txt):\n";
cin >> input;


ifstream in(input.c_str());

if (!in)
{
    cout << "Specified file not found. Exiting... \n\n";
    return 1;
}

char school, alumni;
double GPA, mathSAT, verbalSAT;
int liberalArtsSchoolSeats = 5, musicSchoolSeats = 3, i = 0;

while (in >> school >> GPA >> mathSAT >> verbalSAT >> alumni)
{

    i++;

    cout << "Applicant #: " << i << endl;
    cout << "School = " << school;
    cout << "\tGPA = " << GPA;
    cout << "\tMath = " << mathSAT;
    cout << "\tVerbal = " << verbalSAT;
    cout << "\tAlumnus = " << alumni << endl;

    if (school == 'L')
    {
        cout << "Applying to Liberal Arts\n";

        if (liberalArtsSchoolSeats > 0)
        {

            if (alumni == 'Y')
            {

                if (GPA < 3.0)
                {
                    cout << "Rejected - High school Grade is too low\n\n";
                }

                else if (mathSAT + verbalSAT < 1000)
                {
                    cout << "Rejected - SAT is too low\n\n";
                }

                else
                {
                    cout << "Accepted to Liberal Arts!!\n\n";
                    liberalArtsSchoolSeats--;
                }
            }

            else
            {
                if (GPA < 3.5)
                {
                    cout << "Rejected - High school Grade is too low\n\n";
                }

                else if (mathSAT + verbalSAT < 1200)
                {
                    cout << "Rejected - SAT is too low\n\n";
                }

                else
                {
                    cout << "Accepted to Liberal Arts\n\n";
                    liberalArtsSchoolSeats--;
                }
            }
        }

        else
        {
            cout << "Rejected - All the seats are full \n";
        }
    }

    else
    {
        cout << "Applying to Music\n";

        if (musicSchoolSeats>0)
        {
            if (mathSAT + verbalSAT < 500)
            {
                cout << "Rejected - SAT is too low\n\n";
            }

            else
            {
                cout << "Accepted to Music\n\n";

                musicSchoolSeats--;
            }
        }

        else
        {
            cout << "Rejected - All the seats are full\n";
        }
    }
    cout << "*******************************\n";
}
return 0;
}

感谢您的帮助！

编辑：删除了绒毛。

为了澄清，该程序确实在VS中编译。它打开文件，但不回显文件中的任何信息，而只是打印＆＃34;按任意键退出。。＆＃34;消息。

Answer 1

您有string input;和cin >> input;。这些语句需要<string>标题，但您没有（明确地）包含它。在某些实现中，您可以免费乘坐游戏，因为<iostream>包含<string>标头。但你不应该。始终包含适当的标题：

#include <string>

没有上面的标题你的代码will compile在Linux上使用g ++（这是你正在使用的）但在使用Visual C ++的Windows上没有。话虽如此，使用std::getline接受来自标准输入的字符串而不是std::cin。

C ++代码适用于Gedit，但不适用于VS.

1 个答案: