jquery从URL获取查询字符串

时间:2011-01-11 10:56:54

标签: javascript jquery query-string

  

可能重复:
  How can I get query string values?

我有以下网址:

http://www.mysite.co.uk/?location=mylocation1

我需要的是从URL中获取location的值到变量中,然后在jQuery代码中使用它:

var thequerystring = "getthequerystringhere"

$('html,body').animate({scrollTop: $("div#" + thequerystring).offset().top}, 500);

有没有人知道如何使用JavaScript或jQuery获取该值?

5 个答案:

答案 0 :(得分:466)

来自:http://jquery-howto.blogspot.com/2009/09/get-url-parameters-values-with-jquery.html

这就是你所需要的:)

以下代码将返回包含URL参数的JavaScript对象:

// Read a page's GET URL variables and return them as an associative array.
function getUrlVars()
{
    var vars = [], hash;
    var hashes = window.location.href.slice(window.location.href.indexOf('?') + 1).split('&');
    for(var i = 0; i < hashes.length; i++)
    {
        hash = hashes[i].split('=');
        vars.push(hash[0]);
        vars[hash[0]] = hash[1];
    }
    return vars;
}

例如,如果您有URL:

http://www.example.com/?me=myValue&name2=SomeOtherValue

此代码将返回:

{
    "me"    : "myValue",
    "name2" : "SomeOtherValue"
}

你可以这样做:

var me = getUrlVars()["me"];
var name2 = getUrlVars()["name2"];

答案 1 :(得分:156)

要从当前网址检索整个查询字符串,从?字符开始,您可以使用

location.search

https://developer.mozilla.org/en-US/docs/DOM/window.location

示例:

// URL = https://example.com?a=a%20a&b=b123
console.log(location.search); // Prints "?a=a%20a&b=b123" 

关于检索特定的查询字符串参数,尽管存在URLSearchParamsURL等类,但目前Internet Explorer不支持它们,应该避免使用它们。相反,你可以尝试这样的事情:

/**
 * Accepts either a URL or querystring and returns an object associating 
 * each querystring parameter to its value. 
 *
 * Returns an empty object if no querystring parameters found.
 */
function getUrlParams(urlOrQueryString) {
  if ((i = urlOrQueryString.indexOf('?')) >= 0) {
    const queryString = urlOrQueryString.substring(i+1);
    if (queryString) {
      return _mapUrlParams(queryString);
    } 
  }

  return {};
}

/**
 * Helper function for `getUrlParams()`
 * Builds the querystring parameter to value object map.
 *
 * @param queryString {string} - The full querystring, without the leading '?'.
 */
function _mapUrlParams(queryString) {
  return queryString    
    .split('&') 
    .map(function(keyValueString) { return keyValueString.split('=') })
    .reduce(function(urlParams, [key, value]) {
      if (Number.isInteger(parseInt(value)) && parseInt(value) == value) {
        urlParams[key] = parseInt(value);
      } else {
        urlParams[key] = decodeURI(value);
      }
      return urlParams;
    }, {});
}

您可以使用以上内容:

// Using location.search
let urlParams = getUrlParams(location.search); // Assume location.search = "?a=1&b=2b2"
console.log(urlParams); // Prints { "a": 1, "b": "2b2" }

// Using a URL string
const url = 'https://example.com?a=A%20A&b=1';
urlParams = getUrlParams(url);
console.log(urlParams); // Prints { "a": "A A", "b": 1 }

// To check if a parameter exists, simply do:
if (urlParams.hasOwnProperty('parameterName') { 
  console.log(urlParams.parameterName);
}

答案 2 :(得分:26)

使用jQuery和JS直接执行此操作的简单方法,只需在Chrome或Firefox中查看控制台即可查看输出...

  var queries = {};
  $.each(document.location.search.substr(1).split('&'),function(c,q){
    var i = q.split('=');
    queries[i[0].toString()] = i[1].toString();
  });
  console.log(queries);

答案 3 :(得分:17)

看看这个stackoverflow answer

 function getParameterByName(name, url) {
     if (!url) url = window.location.href;
     name = name.replace(/[\[\]]/g, "\\$&");
     var regex = new RegExp("[?&]" + name + "(=([^&#]*)|&|#|$)"),
         results = regex.exec(url);
     if (!results) return null;
     if (!results[2]) return '';
     return decodeURIComponent(results[2].replace(/\+/g, " "));
 }

您可以使用该方法设置动画:

即:

var thequerystring = getParameterByName("location");
$('html,body').animate({scrollTop: $("div#" + thequerystring).offset().top}, 500);

答案 4 :(得分:1)

我们这样做......

String.prototype.getValueByKey = function (k) {
    var p = new RegExp('\\b' + k + '\\b', 'gi');
    return this.search(p) != -1 ? decodeURIComponent(this.substr(this.search(p) + k.length + 1).substr(0, this.substr(this.search(p) + k.length + 1).search(/(&|;|$)/))) : "";
};