Question

下面是我试图处理的XML文件类型的示例。如果我只有一个部分以及附带的数字/字符，我可以处理数据提取，而不需要＆＃39; if（！reader.EOF）＆＃39;控制结构。但是，当我尝试包含此结构以便我可以循环回检查另一个部分，数字和字符组时，它会死锁。

有关如何正确执行此操作的任何建议吗？这是我脑海中最有效的想法。我是从XMLs读取数据的新手。

示例Xml：

<?xml version="1.0" encoding="UTF-8"?>
<note>
  <part>100B</part>
  <number>45</number>
  <character>a</character>

  <part>100C</part>
  <number>55</number>
  <character>b</character>
</note>

代码：

String part = "part";
String number = "number";
String character = "character";
String appendString = "";
StringBuilder sb = new StringBuilder();

try
{
    XmlTextReader reader = new XmlTextReader("myPath");
    while (reader.Read())
    {
        switch (reader.NodeType)
        {
            case XmlNodeType.Element: // The node is an element.

                myLabel:
                if (reader.Name == part)
                {
                    part = reader.ReadInnerXml();
                }
                if (reader.Name == number)
                {
                    number = reader.ReadInnerXml();
                    number = double.Parse(number).ToString("F2"); //format num
                }
                if (reader.Name == character)
                {
                    character = reader.ReadInnerXml();
                }

                //new string
                appendString = ("Part: " + part + "\nNumber: " + number +
 "\nCharacter: " + character + "\n");

                //concatenate
                sb.AppendLine(appendString);

                if (reader.EOF != true)
                {
                    Debug.Log("!eof");
                    part = "part";
                    number = "number";
                    character = "character";
                    goto myLabel;
                }

                //print fully concatenated result
                sb.ToString();

                //reset string builder
                sb.Length = 0;

                break;
        }
    }
}
catch (XmlException e)
{
    // Write error.
    Debug.Log(e.Message);
}
catch (FileNotFoundException e)
{
    // Write error.
    Debug.Log(e);
}
catch(ArgumentException e)
{
    // Write error.
    Debug.Log(e);
}

Answer 1

XmlReader类有许多有用的方法。使用它。

见：

var sb = new StringBuilder();

using (var reader = XmlReader.Create("test.xml"))
{
    while (reader.ReadToFollowing("part"))
    {
        var part = reader.ReadElementContentAsString();
        sb.Append("Part: ").AppendLine(part);

        reader.ReadToFollowing("number");
        var number = reader.ReadElementContentAsDouble();
        sb.Append("Number: ").Append(number).AppendLine();

        reader.ReadToFollowing("character");
        var character = reader.ReadElementContentAsString();
        sb.Append("Character: ").AppendLine(character);
    }
}

Console.WriteLine(sb);

Answer 2

亚历山大的答案很好，我只想根据Jon Skeet的评论使用XDocument添加样本：

var sb = new StringBuilder();
var note = XDocument.Load("test.xml").Root.Descendants();            
foreach (var el in note)
{                
    sb.Append(el.Name).Append(": ").AppendLine(el.Value);               
}
Console.WriteLine(sb);

如何正确循环XmlTextReader（C＃）？

2 个答案: