如何存储itertools查询的输出

Question

我有以下查询

for key, group in itertools.groupby(r, lambda item: item['b_id']):
        print {key: [x['a_id'] for x in group]}

给出输出

{'0d687c94c5f4': ['12345', '67890']}
{'9ec34be3d535': ['23857', '84596']}
{None: ['d82ebe9815cc']}

如何将其存储到变量以访问其内容

尝试了data = {key：[x [＆＃39; a_id＆＃39;] for x in group]}但是只给出了循环中的最后一个值{None：[＆＃39; d82ebe9815cc＆＃39;]}

>>data 
>>{None: ['d82ebe9815cc']}

Answer 1

您正在每次迭代时使用单个键创建一个新字典。相反，首先定义一个字典，然后在循环中添加键：

data = {key: [x['a_id'] for x in group] for key, group in
        itertools.groupby(r, lambda item: item['b_id'])}

或者，您可以使用字典理解（Python 2.7 +）：

https://www.googleapis.com/auth/drive
https://www.googleapis.com/auth/drive.file
https://www.googleapis.com/auth/spreadsheets