Question

这是一个例子

变量1：

$encodedtoday = MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'Mark')->count();

变量2：

$encodedtoday = MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'Michael')->count();

变量3：

$encodedtoday = MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'John')->count();

我知道这可以在数组或其他东西中完成。请告诉我

Answer 1

试试这样：

$encodedtoday = MemberProfile::whereDate('created_at', '=', $today )
->whereIn('encoded_by', ['Mark','Michael','John'])->count();

希望这有帮助

Answer 2

您可以创建一个由名称编码的数组，然后传递给whereIn条件，如下所示：

$encoded_by = ['Mark','Michael','John'];
$encodedtoday = MemberProfile::whereDate('created_at', '=', $today)
->whereIn('encoded_by', $encoded_by)->count();
return $encodedtoday;

Answer 3

您可以定义$encodedtoday = 0; 然后继续为所有人添加计数：

$encodedtoday += MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'Mark')->count();

$encodedtoday += MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'Michael')->count();

$encodedtoday += MemberProfile::whereDate('created_at', '=', $today )
->where('encoded_by', 'John')->count();

所以在这里，$encodedtoday将有最终计数。

如何在laravel中组合两个或多个变量

3 个答案: