Question

我在我的网站上使用自定义类进行模板化。我刚遇到一种情况，我需要同步附加一个模板。

模板对象数组在结构和数据上非常相似，但是，数组＃2包含几个子数组，它们是数组＃1的子元素。

数组＃1

    0 => 
        object(Template)[59]
          protected 'file' => string 'template/completed.tpl'
          protected 'values' => 
            array (size=3)
              'part' => string 'door'
              'part_status' => string 'warehouse'
              'part_type' => string 'consumable'
    1 => 
        object(Template)[61]
           protected 'file' => string 'template/completed.tpl'
           protected 'values' => 
             array (size=4)
              'partNum' => string '3741852'
              'part' => string 'bolt'
              'part_status' => string 'shipped'
              'part_type' => string 'consumable'
    2 => 
        object(Template)[63]
          protected 'file' => string 'template/completed.tpl'
          protected 'values' => 
            array (size=4)
              'partNum' => string '3741777'
              'part' => string 'frame'
              'part_status' => string 'shipped'
              'part_type' => string 'consumable'
    10 => (RELATED TO INDEX 10 IN ARRAY #2 HOWEVER NO SUBARRAYS)
         object(Template)[65]
          protected 'file' => string 'template/completed.tpl'
          protected 'values' => 
            array (size=4)
              'partNum' => string '3849999'
              'part' => string 'cable'
              'part_status' => string 'backorder'
              'part_type' => string 'consumable'
    ...

数组＃2

0 => 
    object(Template)[33]
      protected 'file' => string 'template/details.tpl'
      protected 'values' => 
        array (size=3)
          'part' => string 'door'
          'part_status' => string 'warehouse'
          'part_type' => string 'consumable'
1 => 
    object(Template)[35]
       protected 'file' => string 'template/details.tpl'
       protected 'values' => 
         array (size=4)
          'partNum' => string '3741852'
          'part' => string 'bolt'
          'part_status' => string 'shipped'
          'part_type' => string 'consumable'
2 => 
    object(Template)[37]
      protected 'file' => string 'template/details.tpl'
      protected 'values' => 
        array (size=4)
          'partNum' => string '3741852'
          'part' => string 'bolt'
          'part_status' => string 'shipped'
          'part_type' => string 'consumable'
...
10 =>
  array (size=2)
    0 =>
      object(Template)[44]
        protected 'file' => string 'template/details.tpl'
        protected 'values' => 
          array (size=4)
            'partNum' => string '3741852'
            'part' => string 'bolt'
            'part_status' => string 'shipped'
            'part_type' => string 'consumable'
    1 =>
    ...

我的想法是将两个数组合并然后循环通过它们但我不知道该怎么做。我首先考虑array_merge，但它将数据附加在一起并保持相同的索引，这不是我需要的。我希望找到一种方法来保持相同的父索引，然后添加每个索引自己的子索引。还有阵列＃2具有子阵列的问题。我还想过尝试同时遍历两个数组，但这似乎是一种混乱的方式。

0 => 
    array (size=2)
      0 =>
          object(Template)[59]
             protected 'file' => string 'template/completed.tpl'
             protected 'values' => 
               array (size=3)
                 'part' => string 'door'
                 'part_status' => string 'warehouse'
                 'part_type' => string 'consumable'
       1 =>
          object(Template)[33]
            protected 'file' => string 'template/details.tpl'
            protected 'values' => 
              array (size=4)
                'partNum' => string '3741852'
                'part' => string 'door'
                'part_status' => string 'warehouse'
                'part_type' => string 'consumable'
1 =>
    array (size=2)
      0 =>
          object(Template)[61]
             protected 'file' => string 'template/completed.tpl'
             protected 'values' => 
               array (size=4)
                'partNum' => string '3741852'
                'part' => string 'handle'
                'part_status' => string 'backorder'
                'part_type' => string 'consumable'
...

Answer 1

你可以这样做： -

$final_array = [];

foreach($array1 as $key=>$arr){
 $final_array[$key] = [$arr,$array2[$key]];
}
print_r($final_array);

如何在不合并的情况下组合两个具有相同索引的多维数组？

1 个答案: