Question

如何从Scanner打印多个字符串，因为没有要调出的数组，而且我仍然坚持如何生成输出。

当用户输入do-while时，我的#循环将停止。在打印出结果的部分之前似乎很好，如果我放strResult我只能看到最后一个用户输入字符串。

以下是我目前的代码：

import java.util.Scanner;
public class SecretMessage {

    public static void main(String[] args) {
        int count =0;
        int i =0;
        //char ch;<<<<<<<<<< I need this for converting the string to char
        Scanner sc = new Scanner(System.in);
        //String result[] = new String[count];<<<<<<<<purposedly for array 
        String input ="";
        String strResult ="";


        do  {
            System.out.print("Enter your text :");
            input=sc.nextLine();
            count++;
        }

        while (!input.equals("#"));
        {
            System.out.print("Result :\n");

            strResult = "Case #"+(count-1)+" :"+input;
            //result[count] = strResult;<<<<<<to represent all result
        }       

        for (i=0;i<(count-1);i++) {

            System.out.println(" "+strResult);

        }
    }
}

Answer 1

使用StringBuilder：In Java, how to append a string more efficiently?

    StringBuilder stringBuilder = new StringBuilder();

    do  {
        System.out.print("Enter your text :");
        input=sc.nextLine();
        stringBuilder.append(input);
        count++;
    }

    while (!input.equals("#"));
    {
        System.out.print("Result :\n");

        strResult = "Case #"+(count-1)+" :"+stringBuilder.toString();
        //result[count] = strResult;<<<<<<to represent all result
    }

Answer 2

您可以使用ArrayList

    ArrayList list = new ArrayList();


    do  {
       System.out.print("Enter your text :");
       input=sc.nextLine();
       list.add(input);
       count++;
       }

   while (!input.equals("#"));
{
       System.out.print("Result :\n");

       strResult = "Case #"+(count-1)+" :"+input;
       //result[count] = strResult;<<<<<<to represent all result
       }       

   for (i=0;i<list.size()-1;i++) {

       System.out.println("Case #" +  (i+1) + " " + list.get(i));

   }

Java - 在无限循环时返回do中的多个字符串用户输入

2 个答案: