Question

到目前为止我的代码：

$query = 'INSERT INTO articles(id, name, picture, url, origAmount, currAmount, added) VALUES ';

$insertQuery = array();
$insertData = array();

$date = getDate();

foreach ($articles as $article) {
    $insertQuery[] = '(?,?,?,?,?,?,?)';
    $insertData[] = $article->id;
    $insertData[] = $article->name;
    $insertData[] = $article->picture;
    $insertData[] = $article->url;
    $insertData[] = $article->amount;
    $insertData[] = $article->amount;
    $insertData[] = $date['year'] . '-' . $date['mon'] . '-' . $date['mday'];
}

if(!empty($insertQuery)) {          
    $query .= implode(', ', $insertQuery);
    $handle = $this->link->prepare($query);
    $handle->execute($insertData);
}

如果id已经存在，我想只更新currAmount。我试过了

$insertQuery[] = '(?,?,?,?,?,?,?) ON DUPLICATE KEY UPDATE currAmount = (currAmount)';

给出了

＆＃39; SQLSTATE [42000]：语法错误或访问冲突：1064 [...]附近＆＃39;（＆＃39; 0192801635＆＃39;，＆＃39; The Renaissance A Ve＆＃39;在第1行＆＃39;

所以行的文字内容虽然在空表上很好地插入，但内容本身并不是问题。

我该怎么做？

编辑：解决了它

在内爆之后，添加了

$query .= ' ON DUPLICATE KEY UPDATE currAmount = VALUES(currAmount)';

谢谢大家。

Answer 1

... ON DUPLICATE KEY UPDATE currAmount=values(currAmount)

您忘记添加值关键字

<强>更新完整的例子：

$insertQuery[] = '(?,?,?,?,?,?,?) ON DUPLICATE KEY UPDATE currAmount=values(currAmount)';

Answer 2

做这样的事情

foreach ($articles as $article) {
  $insertQuery = '(?,?,?,?,?,?,?) ON DUPLICATE KEY UPDATE currAmount = (currAmount)';
  $insertData = $article->id;
  $insertData = $article->name;
  $insertData = $article->picture;
  $insertData = $article->url;
  $insertData = $article->amount;
  $insertData = $article->amount;
  $insertData = $date['year'] . '-' . $date['mon'] . '-' . $date['mday'];

  if(!empty($insertQuery)) {          
    $query .= implode(', ', $insertQuery);
    $handle = $this->link->prepare($query);
    $handle->execute($insertData);
  }
}

在带有数组

2 个答案: