Question

我尝试使用Matplotlib中的这个矩形选择器示例来裁剪图像，但每次运行此代码时，它都会显示“NameError：name'x1'未定义”，但我已将它们定义为全局变量并命名它们在line_select_callback函数中。我原本认为当我点击并释放时，我点击和释放的坐标数据将保存在x1，x2，y1，y2中，然后我将能够使用它们来裁剪原始图像，但似乎出现了问题，我不知道为什么。

from matplotlib.widgets import RectangleSelector
import numpy as np
import matplotlib.pyplot as plt
from PIL import Image

def line_select_callback(eclick, erelease):

    global x1, y1, x2, y2
    'eclick and erelease are the press and release events'
    x1, y1 = eclick.xdata, eclick.ydata
    x2, y2 = erelease.xdata, erelease.ydata
    print("(%3.2f, %3.2f) --> (%3.2f, %3.2f)" % (x1, y1, x2, y2))
    print(" The button you used were: %s %s" % (eclick.button, erelease.button))


def toggle_selector(event):
    print(' Key pressed.')
    if event.key in ['Q', 'q'] and toggle_selector.RS.active:
        print(' RectangleSelector deactivated.')
        toggle_selector.RS.set_active(False)
    if event.key in ['A', 'a'] and not toggle_selector.RS.active:
        print(' RectangleSelector activated.')
        toggle_selector.RS.set_active(True)


fig = plt.figure()
ax = fig.add_subplot(111)
filename="C:\\Users\\motorsgroup\\Desktop\\test.png"
im = Image.open(filename)
arr = np.asarray(im)
plt_image=plt.imshow(arr)

print("\n      click  -->  release")

# drawtype is 'box' or 'line' or 'none'
toggle_selector.RS = RectangleSelector(ax, line_select_callback,
                                       drawtype='box', useblit=True,
                                      button=[1, 3],  # don't use middle button
                                       minspanx=5, minspany=5,
                                       spancoords='pixels',
                                       interactive=True)
plt.connect('key_press_event', toggle_selector)
plt.show()

newim = arr[int(x1):int(x2),int(y2):int(y1)]

非常感谢你！

使用matplotlib矩形选择器

0 个答案: