DAO如何映射SQL函数返回的字段?

时间:2017-10-03 11:22:45

标签: java hibernate dropwizard

我正在为我的API使用dropwizard框架。我有一个命名查询如下:

@NamedQuery(name = "com.myapp.entity.MyEntity.findByMatchId", query = "SELECT test.name, count(test) as count FROM MyEntity as test,Entity1 as d where test.drug=d.id and test.drug.id= :drugId group by test.name") })

我将count(test)函数的结果作为名称count返回。以下是我的实体类:

@NamedQuery(name = "com.myapp.entity.MyEntity.findByMatchId", query = "SELECT test.name, count(test) as count FROM MyEntity as test,Entity1 as d where test.drug=d.id and test.drug.id= :drugId group by test.name") })

@Entity
@Table(name = "my_entity")
@NamedQueries({
        @NamedQuery(name = "com.myapp.entity.MyEntity.findByMatchId", query = "SELECT test.name, count(test) as count FROM MyEntity as test,Entity1 as d where test.drug=d.id and test.drug.id= :drugId group by test.name") }))
public class MyEntity {

        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        private Long id;

        @Column(name = "name")
        private String name;

        @JsonBackReference("drug_id")
        @ManyToOne(fetch = FetchType.LAZY)
        @JoinColumn(name = "drug_id", nullable = false)
        private Drug drug;

        @Column(name = "timestamp", nullable = false)
        private Date timestamp;

        // This value is not getting mapped 
        private Long count;

        public Long getId() {
            return id;
        }

        public void setId(Long id) {
            this.id = id;
        }

        public String getName() {
            return name;
        }

        public void setName(String name) {
            this.name = name;
        }

        public Drug getDrug() {
            return drug;
        }

        public void setDrug(Drug drug) {
            this.drug = drug;
        }

        public Date getTimestamp() {
            return timestamp;
        }

        public void setTimestamp(Date timestamp) {
            this.timestamp = timestamp;
        }

        public SideEffectSeverity getSideEffectSeverity() {
            return sideEffectSeverity;
        }

        public void setSideEffectSeverity(SideEffectSeverity sideEffectSeverity) {
            this.sideEffectSeverity = sideEffectSeverity;
        }

        public Long getCount() {
            return count;
        }

        public void setCount(Long count) {
            this.count = count;
        }

    }

我可以在这里做什么来获得正确的映射,其中count函数的值为count。

为什么我的映射没有正确发生,我是否必须给它一些注释?

2 个答案:

答案 0 :(得分:2)

您是否从上述查询中获得了任何结果?

如果是,那么请注意,count()函数的返回类型将很长。所以希望你试图用DTO映射响应(它应该包含两个字段作为名称和计数)。

答案 1 :(得分:0)

您使用的是OracleSQL还是POSTgreSQL?

Count是一个保留字,重命名你的列会像这样修复

std::function