Question

我想从此输出获取id并更新数据库我如何从此查询中获取？

$text = "<test>output: 1;outdoor: 456;<test>
    <test>output: 2;outdoor: 4564;<test>
    <test>output: 3;outdoor: 645;<test>
    <test>output: 4;outdoor: 765;<test>"; 

mysql_query("UPDATE test SET outdoor = $outdoor" where id = $output);

Answer 1

请尝试我的回答

<?php 
    $text = "<test>output: 1;outdoor: 456;<test>
    <test>output: 2;outdoor: 4564;<test>
    <test>output: 3;outdoor: 645;<test>
    <test>output: 4;outdoor: 765;<test>";
    $text_arr = explode("\n",$text);

    foreach($text_arr as $val_text_arr){
        /*echo $val_text_arr."<bR>";*/
        $output = explode(";",explode("output: ",$val_text_arr)[1])[0];
        echo "output ".$output ."\n";
        $outdoor = explode(";",explode("outdoor: ",$val_text_arr)[1])[0];
        echo "outdoor ".$outdoor ."\n";
        /*you can update here ypur query*/
        mysql_query("UPDATE test SET outdoor = $outdoor" where id = $output);
    }
     ?>

输出：

output 1
outdoor 456
output 2
outdoor 4564
output 3
outdoor 645
output 4
outdoor 765

php链接我试试这个 https://eval.in/872778

如何实现输出id和更新表

1 个答案: