Question

我需要从字符串中提取路径

例如

title="set key invert ; set bmargin 0 ; set multiplot ; set size 1.0 , 0.33 ; set origin 0.0 , 0.67 ; set format x "" ; set xtics offset 15.75 "1970-01-01 00:00:00" , 31556736 ; plot "/usr/local/lucid/www/tmp/20171003101438149255.dat" using 1:5 notitle with linespoints ls 2'"

然后预期输出应为

/usr/local/lucid/www/tmp/20171003101438149255.dat

使用awk或grep

Answer 1

sed 方法：

title='set key invert ; set bmargin 0 ; set multiplot ; set size 1.0 , 0.33 ; set origin 0.0 , 0.67 ; set format x "" ; set xtics offset 15.75 "1970-01-01 00:00:00" , 31556736 ; plot "/usr/local/lucid/www/tmp/20171003101438149255.dat" using 1:5 notitle with linespoints ls 2'

sed 's/.* plot "\([^"]\+\).*/\1/' <<<$title
/usr/local/lucid/www/tmp/20171003101438149255.dat

Answer 2

使用grep解决方案，

grep -oP '"\K/[^"]*(?=")' <<< $title

使用awk解决方案，

awk '{match($0,/\/[^"]*/,a);print a[0]}' <<< $title

Answer 3

使用grep缩短正则表达式：

grep -oP 'plot "\K[^"]+' <<< $title
/usr/local/lucid/www/tmp/20171003101438149255.dat

如何从shell脚本中的字符串中提取路径

3 个答案: