Question

我正在尝试获取应用程序加载的第一页。我创建了maven项目，它在web-app下正常运行我在jsp文件夹中创建了一个名为jsp的文件夹我创建了login.jsp 而不是index.jsp，它应该选择jsp文件夹

下的login.jsp

的的web.xml

 <welcome-file-list>   
    <welcome-file>index.jsp</welcome-file>   
  </welcome-file-list>
   <servlet>
        <servlet-name>mvc</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring-config.xml
        </param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>mvc</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

控制器

package com.sanria.estimodelling.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

import com.sanria.estimodelling.dto.LoginDTO;

@Controller
public class SampleController {
    /* Method to return to login page */
    @RequestMapping(value = "login")
    public ModelAndView display() {
        LoginDTO loginDTO = new LoginDTO();
        return new ModelAndView("page-login", "login", loginDTO);
    }
}

Answer 1

我已经改变了我的代码这样的工作正常，任何人都可以审查这个正确的我，如果我知道吗？

Web.xml

<servlet>
            <servlet-name>mvc</servlet-name>
            <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
            <init-param>
                <param-name>contextConfigLocation</param-name>
                <param-value>/WEB-INF/spring-config.xml
            </param-value>
            </init-param>
            <load-on-startup>1</load-on-startup>
        </servlet>
        <servlet-mapping>
            <servlet-name>mvc</servlet-name>
            <url-pattern>/</url-pattern>
        </servlet-mapping>

<强>控制器

package com.sanria.estimodelling.controller;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

import com.sanria.estimodelling.dto.LoginDTO;

@Controller
public class SampleController {
    /* Method to return to login page */
    @RequestMapping(value = "/")
    public ModelAndView display() {
        LoginDTO loginDTO = new LoginDTO();
        return new ModelAndView("page-login", "login", loginDTO);
    }
}

如何在应用程序加载时从弹簧控制器获取欢迎页面

1 个答案: