Question

我有一个表格ABC，其中有2列，PIN和FROM_DATE。我希望PIN分组count > 1，并希望在FROM_DATE列上对结果集进行分区。我试过了，

SELECT pin, from_date, COUNT(*) AS repetition 
from ABC
GROUP BY pin
HAVING COUNT(*) > 1
ORDER BY from_date;

上述声明给出了'not a GROUP BY expression'错误。如何将所有Group by，having和order by放在一个select语句中？

Answer 1

如果您只想要每个from_date的最新pin，那么：

SELECT pin,
       MAX( from_date ) AS from_date,
       COUNT(*) AS repetition 
FROM   ABC
GROUP BY pin
HAVING COUNT(*) > 1
ORDER BY from_date;

如果您希望每个from_date的{{1}}分别为pin，那么from_date中有两个或更多个SELECT pin, from_date, COUNT(*) AS repetition FROM ABC GROUP BY pin, from_date HAVING COUNT(*) > 1 ORDER BY from_date;：

from_date

如果您需要pin个，而SELECT pin, from_date FROM ( SELECT pin, from_date, COUNT(*) OVER( PARTITION BY pin ) AS repetition FROM ABC ) WHERE repetition > 1 ORDER BY from_date;有两个或更多，那么您可以使用分析函数：

FROM microsoft/aspnet:4.6.2
ARG source
WORKDIR /inetpub/wwwroot
COPY ${source:-obj/Docker/publish} .

Answer 2

尝试：

SELECT pin, MAX(from_date), COUNT(*) AS repetition 
from ABC
GROUP BY pin
HAVING COUNT(*) > 1
ORDER BY MAX(from_date);

或者

SELECT pin, MIN(from_date), COUNT(*) AS repetition 
from ABC
GROUP BY pin
HAVING COUNT(*) > 1
ORDER BY MIN(from_date);

Answer 3

您不能使用没有聚合功能的选择列，也不能在group by子句中提及因此，您可以使用子查询获取所需的值，并通过

连接到不在分组中的值

select distinct ABC.pin, ABC.from_date, t.repetition 
from ABC 
inner join  ( 
SELECT pin, COUNT(*) AS repetition 
from ABC
GROUP BY pin
HAVING COUNT(*) > 1 ) t on t.pin = ABC.pin 
order by ABC.from_date

Answer 4

您的select子句中有2个未聚合的属性：pin, from_date但只按其中一个（pin）分组，因此from_date'不是GROUP BY表达式'

考虑：

 SELECT pin, from_date, COUNT(*) AS repetition 
 from ABC
 GROUP BY pin, from_date
 HAVING COUNT(*) > 1
 ORDER BY from_date;

在select语句中分组，拥有和排序

4 个答案: