Question

我有一个联接，返回今天的结果，但我希望它返回昨天的值。

FROM
Person
JOIN Profit 
ON Person.id = Profit.id 
AND [DATE] = CAST(getdate () -1  as Date)

^^这将返回当前日期。

然后我试图返回昨天的日期：

 [DATE] = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), -1)

 [DATE] = DATEADD(day,DATEDIFF(day,0,GETDATE())-1,0)

 [DATE] = dateadd(DD, -1, cast(getdate() as date))

但这些都不起作用。有人可以帮忙吗？感谢

Answer 1

如果你执行

select DATEADD(day, -1, cast(SYSDATETIME() as DATE))
select dateadd(DD, -1, cast(getdate() as date))

然后返回昨天的日期。因此，唯一的问题可能是[DATE]属性的格式。

Answer 2

简单地：

FROM
Person
JOIN Profit 
ON Person.id = Profit.id 
WHERE Table.[DATE] = DATEADD(DAY, -1, GETDATE() );

Answer 3

可能[DATE]也需要转换：

FROM
    Person
JOIN 
    Profit 
ON 
    Person.id = Profit.id 
AND CAST([DATE] as Date) = CAST(getdate () -1  as Date)

Answer 4

如果您不希望时间成为日期的一部分，请使用此选项。

SELECT * 
FROM Person 
    JOIN Profit ON Person.id = Profit.id 
   AND [DATE] = CONVERT(VARCHAR, DATEADD(DAY, -1, GETDATE()), 106)

Answer 5

如果您有包含日期的列：

SELECT * from Person p join Profit pr 
on (p.id = pr.person_id and pr.`date` = SUBDATE(CURDATE(),1))

Answer 6

我认为您应该使用Between，如下所示：

FROM
Person
JOIN Profit 
ON Person.id = Profit.id 
AND [DATE] BETWEEN CONVERT(date, GETDATE()-1) AND CONVERT(date, GETDATE()-1)

在昨天的日期返回结果

6 个答案: