在Qualtrics-SOS

时间:2017-10-03 04:21:48

标签: javascript qualtrics

我是Qualtrics / JavaScript的新手......希望得到帮助

Var block1= [parseInt("${q://QID664/SelectedAnswerRecode/1}"), parseInt("${q://QID664/SelectedAnswerRecode/2}"), parseInt("${q://QID664/SelectedAnswerRecode/3}"), parseInt("${q://QID664/SelectedAnswerRecode/4}"), parseInt("${q://QID664/SelectedAnswerRecode/5}"), parseInt("${q://QID664/SelectedAnswerRecode/6}"), parseInt("${q://QID664/SelectedAnswerRecode/7}"), parseInt("${q://QID664/SelectedAnswerRecode/8}"), parseInt("${q://QID664/SelectedAnswerRecode/9}"), parseInt("${q://QID664/SelectedAnswerRecode/10}")];

`for(i=0;i<block1.length;i++) {
`diff_array[i]= block1[i+1]- block1[i]}`

接下来,我想要做以下事情: - 找到数组     num_switch_block1= number of ones in difference array)

-create lambda variable-     lambda_multiplier= [.7, .9, 1.1, 1.3, 1.5, 1.7, 1.9, 2.1, 2.3]

是否有更优雅的方法来增加该数组?我应该将其设置为嵌入数据吗? - lambda_multiplier的多重差分数组

`var mult = multiply(diff_array,lambda_multiplier);`

- 然后将此数组仅减少为非零值     mult.filter (Boolean)

我使用正确的功能/这样做吗?

1 个答案:

答案 0 :(得分:1)

不确定你将对数组mult做什么,但这里是创建它的代码(未经测试):

    var block1= [parseInt("${q://QID664/SelectedAnswerRecode/1}"),
      parseInt("${q://QID664/SelectedAnswerRecode/2}"),
      parseInt("${q://QID664/SelectedAnswerRecode/3}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/4}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/5}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/6}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/7}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/8}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/9}"), 
      parseInt("${q://QID664/SelectedAnswerRecode/10}")];
    var lambda_multiplier = [.7, .9, 1.1, 1.3, 1.5, 1.7, 1.9, 2.1, 2.3];
    var mult = [];
    for(i=0;i<lambda_multiplier.length;i++) {
     mult[i] = (block1[i+1] - block1[i]) * lambda_multiplier[i];
    }
    mult = mult.filter(Number); //remove 0s from mult