我必须制作一个三个不同级别的迷宫，让您随时退出。我已尝试在任何地方插入quit()电话，但我似乎无法让它发挥作用。有人能告诉我我做错了什么吗？我能解决的问题是否容易，或者我的逻辑是否正常？谢谢！ :(
def start():
print('Welcome to the Maze!')
choose_level()
def choose_level():
level = input('Select a level: Easy, Average, or Difficult \n')
if level == 'Easy' or 'easy' or 'EASY' or '1':
return easy()
elif level == 'Average' or 'average' or 'AVERAGE' or '2':
return average()
elif level == 'Difficult' or 'difficult' or 'DIFFICULT' or '3':
return difficult()
def easy():
maze1_list = []
# [Description, North, East, South, West]
maze1_list.append(['Available Directions: East', None, 1, None, None]) #0
maze1_list.append(['Available Directions: East, South, West', None, 2, 3, 0]) #1
maze1_list.append(['Available Directions: West', None, None, None, 1]) #2
maze1_list.append(['Available Directions: North, East', 1, 4, None, None]) #3
maze1_list.append(['Available Directions: South, West', None, None, 5, 3]) #4
current_tile = 0
done = False
directions = {'North' or 'north' or 'NORTH':1, 'East' or 'east' or 'EAST':2, 'South' or 'south' or 'SOUTH':3, 'West' or 'west' or 'WEST':4}
#Source: obtained from <https://stackoverflow.com/questions/46511833/how-do-you-make-a-simple-3x3-maze-on-python-using-lists/46517061#46517061>
#Date: <October 2, 2017>
#Name of Author/Programmer: <Anton vBR>
while not done:
print('')
print(maze1_list[current_tile][0])
x = '0'
available = False
while not available:
while not directions.get(x.title()): #Source: obtained from <http://programarcadegames.com/index.php?chapter=lab_adventure>
#Date: <October 2, 2017>
#Name of Author/Programmer: <Paul Vincent Craven>
if x!='0':
print('Please choose an available direction. ')
x = input('Which direction will you take? \n')
next_move = directions.get(x.title()) #Source: obtained from <http://programarcadegames.com/index.php?chapter=lab_adventure>
#Date: <October 2, 2017>
#Name of Author/Programmer: <Paul Vincent Craven>
next_tile = maze1_list[current_tile][next_move]
if next_tile:
available = True
current_tile = next_tile
elif x == 'quit':
quit()
else:
print('Please choose an availble direction.')
x = '0'
if current_tile == 5:
print('Congratulations! You found the exit. \nGoodbye.')
done = True
# i'm going to cut off the average and difficult levels of my code here
since they're the same concept as the easy level
答案 0 :(得分：0)
def start():
print('Welcome to the Maze!')
maze_list = choose_level()
run_maze(maze_list)
def choose_level():
level = input('Select a level: Easy, Average, or Difficult \n')
# one way of checking a variable against multiple values
if level == 'Easy' or level == 'easy' or level == 'EASY' or level =='1':
maze_list = easy()
# another way of checking a variable against multiple values
elif level in ('Average', 'average', 'AVERAGE', '2'):
maze_list = average()
elif level in ('Difficult', 'difficult', 'DIFFICULT', '3'):
maze_list = difficult()
return maze_list
def average():
maze_list = []
return maze_list
def difficult():
maze_list = []
return maze_list
def easy():
maze1_list = []
# [Description, North, East, South, West]
maze1_list.append(['Available Directions: East', None, 1, None, None]) #0
maze1_list.append(['Available Directions: East, South, West', None, 2, 3, 0 ]) #1
maze1_list.append(['Available Directions: West', None, None, None, 1 ]) #2
maze1_list.append(['Available Directions: North, East', 1, 4, None, None]) #3
maze1_list.append(['Available Directions: South, West', None, None, 5, 3 ]) #4
# solution: East, South, East, South
return maze1_list
def run_maze(maze_list):
'''
# Improper use of dictionary key-value pair definitions
directions = {'N' or 'n' or 'North' or 'north' or 'NORTH':1,
'E' or 'e' or 'East' or 'east' or 'EAST ':2,
'S' or 's' or 'South' or 'south' or 'SOUTH':3,
'W' or 'w' or 'West' or 'west' or 'WEST' :4
}
'''
# proper dictionary definitions. each option must be it's own key value pair.
# since we're using x.title(), we only need title-case variations
directions = {'N' : 1,
'North': 1,
'E' : 2,
'East' : 2,
'S' : 2,
'South': 3,
'W' : 4,
'West' : 4
}
# done when "solved the maze" ("quit" exits the program directly)
done = False
# current location in maze_list
current_tile = 0
while not done:
if maze_list == []:
print("No maze defined.. exiting.")
return
# "I have an available direction from the user."
# available signifies that the user has entered a valid directions
# more importantly, that we do not need to ask for a new value right now.
# I'd probably rename this, and then use it slightly differently
# reset this to False on each pass through this loop
available = False
# you had an extra outter loop here
# loop below could be extracted as a function for requesting valid user input
while not available:
# input from user (menu: (directions)"N", "S", "E", "W", or "Quit")
x = '0' # not necessary to initialize
# Let the user know what directions are "available"
print( " ", maze_list[current_tile][0])#, '(maze_list[current_tile][0])\n')
# accepts the user's: direction, "quit" request, (or garbage)
x = input('Which direction will you take?\n')
if x.title() == 'Quit':
#done = True
#available = True
print("Quitting..")
quit()
# if "quit()" isn't available in this environment..
print("tried to quit.. returning now instead..")
# see here if "quit() does not work":
# https://stackoverflow.com/questions/19747371/python-exit-commands-why-so-many-and-when-should-each-be-used
return
# translate requested direction to a numbered direction
# if user did not enter a direction, use get()'s default parameter
# to set the requested_direction to "None"
requested_direction = directions.get(x.title(), None)
# uses short-circuit evaluation, to first check if requested_direction is "None"
# only then will it check to see if it was an "available" direction
if (requested_direction != None) and (maze_list[current_tile][requested_direction] != None):
# (we can stop asking the user for a direction)
available = True
# else: run this loop again, asking for user directions.
# (the user either entered an unavailable direction, or complete nonsense.)
# we don't need to do anything here, as available==False, and re-enters the while loop
next_move = directions.get(x.title())
next_tile = maze_list[current_tile][next_move]
current_tile = next_tile
# no longer needed.
# if next_tile:
# available = True
# current_tile = next_tile
if current_tile == 5:
print(' Congratulations! You found the exit. \nGoodbye.')
done = True
start()
错误如下：
while loop - 它无法正确更新其值一些需要思考的设计思路：
easy()，average()和difficult()。反过来，这些功能可以简单地用于加载迷宫本身的细节。最后，如果quit()仍然不起作用 ，请参阅此链接