Question

以下位配置接受带有要创建的用户实例的JSON请求主体的HTTP POST，但如果我能让它返回201 Created，我就会受到威胁。有什么想法吗？

@Bean
public IntegrationFlow flow(UserService userService) {
    return IntegrationFlows.from(
            Http.inboundGateway("/users")
            .requestMapping(r -> r.methods(HttpMethod.POST))
            .statusCodeFunction(f -> HttpStatus.CREATED)
            .requestPayloadType(User.class)
            .replyChannel(replyChannel())
            .requestChannel(inputChannel())
        )
        .handle((p, h) -> userService.create((User) p)).get();
}

我尝试在statusCodeFunction上调用HttpRequestHandlerEndpointSpec，但我一定做错了。

Answer 1

答案是statusCodeFunction仅适用于入站适配器（即在途中单向的事物）。有点想问为什么我可以在网关上调用它，但是哼哼......

在enrichHeaders上使用IntegrationFlow就可以了。

@Configuration
@EnableIntegration
@Profile("integration")
public class IntegrationConfiguration {
    @Autowired
    UserService userService;

    @Bean
    public DirectChannel inputChannel() {
        return new DirectChannel();
    }

    @Bean
    public DirectChannel replyChannel() {
        return new DirectChannel();
    }

    @Bean
    public HttpRequestHandlingMessagingGateway httpGate() {
        HttpRequestHandlingMessagingGateway gateway = new HttpRequestHandlingMessagingGateway(true);
        RequestMapping requestMapping = new RequestMapping();
        requestMapping.setMethods(HttpMethod.POST);
        requestMapping.setPathPatterns("/users");
        gateway.setRequestPayloadType(User.class);
        gateway.setRequestMapping(requestMapping);
        gateway.setRequestChannel(inputChannel());
        gateway.setReplyChannel(replyChannel());
        return gateway;
    }

    @Bean
    public IntegrationFlow flow(UserService userService) {
        return IntegrationFlows.from(httpGate()).handle((p, h) -> userService.create((User) p))
                .enrichHeaders(
                        c -> c.header(org.springframework.integration.http.HttpHeaders.STATUS_CODE, HttpStatus.CREATED))
                .get();
    }
}

在Spring Integration Java DSL中设置Response Http：InboundGateway StatusCode

1 个答案: