Question

我想创建具有

的微调器

8：00-8：30 AM 8：30-9：00 AM 9：00-9：30上午

我使用ArrayList完成的时间段如

8:00 AM
9:00 AM
10:00 AM

等等。

我得到了像

这样的arraylist

ArrayList[08:00:AM, 09:00:AM, 10:00:AM, 11:00:AM, 12:00:PM, 13:00:PM, 14:00:PM, 15:00:PM, 16:00:PM, 17:00:PM, 18:00:PM, 19:00:PM, 20:00:PM, 21:00:PM]

这是我的代码：

public class MainActivity extends AppCompatActivity {

    ArrayList<String> hours = new ArrayList<String>();

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        initCustomTimeSpinner();
    }

    private void initCustomTimeSpinner() {

        Spinner spinnerCustom = (Spinner) findViewById(R.id.spinner2);

        Calendar cal = Calendar.getInstance();
        SimpleDateFormat sdf = new SimpleDateFormat("HH:mm:a");

        SimpleDateFormat startHourFormat = new SimpleDateFormat("HH");
        cal.set(Calendar.HOUR_OF_DAY, 8);
        cal.set(Calendar.MINUTE, 0);
        cal.set(Calendar.SECOND, 0);

        int startHour = Integer.parseInt(startHourFormat.format(cal.getTime()));
        Log.e("startHour", Integer.toString(startHour));

        Log.e("withot format Starttime", cal.getTime().toString());

        SimpleDateFormat endHourFormat = new SimpleDateFormat("HH");
        cal.set(Calendar.HOUR_OF_DAY, 21);
        cal.set(Calendar.MINUTE, 0);
        cal.set(Calendar.SECOND, 0);

        int endHour = Integer.parseInt(endHourFormat.format(cal.getTime()));
        Log.e("endHour", Integer.toString(endHour));

        Log.e("withot format End time", cal.getTime().toString());

        String test = sdf.format(cal.getTime());
        Log.e("TEST", test);

        for (int i = startHour; i <= endHour; i++) {

            cal.set(Calendar.HOUR_OF_DAY, i);
            hours.add(sdf.format(cal.getTime()));
            System.out.println("ArrayList" + hours);
        }
    }
}

Answer 1

以下是使用Java 8 Time API构建时隙的简单示例：

public static void printTimeSlots(LocalTime startTime, LocalTime endTime, int slotSizeInMinutes) {
    for (LocalTime time = startTime, nextTime; time.isBefore(endTime); time = nextTime) {
        nextTime = time.plusMinutes(slotSizeInMinutes);
        if (nextTime.isAfter(endTime))
            break; // time slot crosses end time
        System.out.println(time + "-" + nextTime);
    }
}

测试

printTimeSlots(LocalTime.parse("08:00"), LocalTime.parse("17:00"), 30);

输出

08:00-08:30
08:30-09:00
09:00-09:30
09:30-10:00
10:00-10:30
10:30-11:00
11:00-11:30
11:30-12:00
12:00-12:30
12:30-13:00
13:00-13:30
13:30-14:00
14:00-14:30
14:30-15:00
15:00-15:30
15:30-16:00
16:00-16:30
16:30-17:00

测试＃2，显示未对齐的结束时间

printTimeSlots(LocalTime.parse("10:05"), LocalTime.parse("11:55"), 15);

10:05-10:20
10:20-10:35
10:35-10:50
10:50-11:05
11:05-11:20
11:20-11:35
11:35-11:50

当然，如果您不想在几分钟内限制广告位尺寸，则可以使用TemporalAmount而不是分钟数：

public static void printTimeSlots(LocalTime startTime, LocalTime endTime, TemporalAmount amountToAdd) {
    for (LocalTime time = startTime, nextTime; time.isBefore(endTime); time = nextTime) {
        nextTime = time.plus(amountToAdd);
        if (nextTime.isAfter(endTime))
            break; // time slot crosses end time
        System.out.println(time + "-" + nextTime);
    }
}

测试

printTimeSlots(LocalTime.parse("10:05:15"),
               LocalTime.parse("11:55:00"),
               Duration.ofMinutes(15).plusSeconds(25));

10:05:15-10:20:40
10:20:40-10:36:05
10:36:05-10:51:30
10:51:30-11:06:55
11:06:55-11:22:20
11:22:20-11:37:45
11:37:45-11:53:10

如何在上午8:00，上午8:30，上午9:00，上午9:30等阵列列表中获取30分钟步骤，依此类推至晚上9:00？

1 个答案: