我一直试图弄清楚如何为谷歌创建合适的数组 时间表图表，如高级示例：
https://developers.google.com/chart/interactive/docs/gallery/timeline#an-advanced-example
我有一个函数可以执行查询并返回所需的数组，但单独返回代码：
$data0 = array();
$data1 = array();
$array = array();
$array[] = array("v" => $name . ' ' . $id);
$array[] = array("v" => (string) 'Process 1');
$array[] = array("v" => (string) $date1);
$array[] = array("v" => (string) $date2);
$data0[] = array("c" => $array);
$array = array();
$array[] = array("v" => $name . ' ' . $id);
$array[] = array("v" => (string) 'Process 2');
$array[] = array("v" => (string) $date3);
$array[] = array("v" => (string) $date4);
$data1[] = array("c" => $array);
return $data0;
//return array($data0,$data1)
// array merge did not work for me in this scenario
对于图形我遍历一个返回多个值的查询结果，我需要从每个值中检索几个日期：
while ($rows = mysqli_fetch_object($query)) {
list($data0,$data1) = ep_timeline($dbcon, $rows->id, $periodo);
$temp[] = $data0;
//$temp[] = $data0+$data1; <-- not work
}
$table['rows'] = $temp;
$jsonTable = json_encode($table);
如果我只使用一个数组，则图表有效。 $ data0，但我需要从两个数组创建一个单独的数组，例如$ data0数组是这样的：
Array
(
[c] => Array
(
[0] => Array
(
[v] => Proyect 1
)
[1] => Array
(
[v] => Process 1
)
[2] => Array
(
[v] => Date(2017,7,11)
)
[3] => Array
(
[v] => Date(2017,7,14)
)
)
)
和$ data1如下所示：
Array
(
[c] => Array
(
[0] => Array
(
[v] => Proyect 1
)
[1] => Array
(
[v] => Process 2
)
[2] => Array
(
[v] => Date(2017,7,14)
)
[3] => Array
(
[v] => Date(2017,7,24)
)
)
)
最终数组应如下所示：
Array
(
[c] => Array
(
[0] => Array
(
[v] => Proyect 1
)
[1] => Array
(
[v] => Process 1
)
[2] => Array
(
[v] => Date(2017,7,11)
)
[3] => Array
(
[v] => Date(2017,7,14)
)
)
)
Array
(
[c] => Array
(
[0] => Array
(
[v] => Proyect 1
)
[1] => Array
(
[v] => Process 2
)
[2] => Array
(
[v] => Date(2017,7,14)
)
[3] => Array
(
[v] => Date(2017,7,24)
)
)
)
但我找不到创造它的方法，任何灯光都会受到赞赏
此致