出于某种原因,Valgrind似乎在调用ifstream.read的行中(在searchInFile函数中)进行无效写入。 gdb似乎在同一行上有段错误,但我无法弄清楚问题。如果正在调用读取函数,那么如何进行写入操作?
#include <iostream>
#include <fstream>
#include <cstring>
#include <cstdlib>
#define FILENAME "./test.dat"
using namespace std;
struct record
{
long long int phoneNumber;
char name[10];
char address[75];
};
int searchInFile(long long int phoneNo)
{
/*
Search if a record with the given phone no.
exists in the file. Returns the number of
records before the required record. Returns
-1 if no such record exists.
*/
int ctr = 0;
record * buffer = NULL;
ifstream file(FILENAME, ios::binary);
while(file.read( reinterpret_cast<char*>(buffer), sizeof(record)))
{
if(buffer->phoneNumber == phoneNo)
{
file.close();
return(ctr);
}
ctr++;
}
file.close();
if(buffer->phoneNumber == phoneNo)
return(ctr);
return(-1);
}
void displayRecord(long long int phoneNo)
{
/*
Displays the record with given phone no.
*/
int location = searchInFile(phoneNo);
record * buffer = NULL;
if(location == -1)
cout << "Invalid Number! No such record exists!" << endl;
else
{
ifstream file(FILENAME, ios::binary);
cout << "Reading Error Code: " << file.read(reinterpret_cast<char*>(buffer), sizeof(record));
cout << "Phone Number: " << buffer->phoneNumber << endl;
cout << "Name: " << buffer->name << endl;
cout << "Address: " << buffer->address << endl;
file.close();
}
}
void saveRecord(record toSave)
{
/*
Saves a new record to file
*/
ofstream ofile(FILENAME, ios::app | ios::binary);
//ofile.seekp(0, ios::end);
ofile.write( reinterpret_cast<char*>(&toSave), sizeof(record));
ofile.close();
}
int main()
{
record test = {(long long int)9988776655, "Debug", "Address of Debugger"};
saveRecord(test);
displayRecord((long long int) 9988776655);
return(0);
}
这是Valgrind和gdb的输出:
Syscall param write(buf) points to uninitialised byte(s)
at 0x543B870: __write_nocancel (syscall-template.S:81)
by 0x4EB18D5: ??? (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE9A77: std::basic_filebuf<char, std::char_traits<char> >::_M_convert_to_external(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EEA4D2: std::basic_filebuf<char, std::char_traits<char> >::overflow(int) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE9CA2: std::basic_filebuf<char, std::char_traits<char> >::_M_terminate_output() (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE9D4A: std::basic_filebuf<char, std::char_traits<char> >::close() (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EEBB4C: std::basic_ofstream<char, std::char_traits<char> >::close() (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4011A5: saveRecord(record) (test.cpp:84)
by 0x4012F1: main (test.cpp:91)
Address 0x5a1b31d is 93 bytes inside a block of size 8,192 alloc'd
at 0x4C2B8A8: operator new[](unsigned long) (vg_replace_malloc.c:423)
by 0x4EE98AB: std::basic_filebuf<char, std::char_traits<char> >::_M_allocate_internal_buffer() (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE9EC1: std::basic_filebuf<char, std::char_traits<char> >::open(char const*, std::_Ios_Openmode) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EEB747: std::basic_ofstream<char, std::char_traits<char> >::basic_ofstream(char const*, std::_Ios_Openmode) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x40117E: saveRecord(record) (test.cpp:81)
by 0x4012F1: main (test.cpp:91)
Invalid write of size 1
at 0x4ED338E: std::basic_streambuf<char, std::char_traits<char> >::xsgetn(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE8D0D: std::basic_filebuf<char, std::char_traits<char> >::xsgetn(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EB4CAA: std::istream::read(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x400EDD: searchInFile(long long) (test.cpp:30)
by 0x400FAA: displayRecord(long long) (test.cpp:55)
by 0x401300: main (test.cpp:92)
Address 0x0 is not stack'd, malloc'd or (recently) free'd
Process terminating with default action of signal 11 (SIGSEGV)
Access not within mapped region at address 0x0
at 0x4ED338E: std::basic_streambuf<char, std::char_traits<char> >::xsgetn(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EE8D0D: std::basic_filebuf<char, std::char_traits<char> >::xsgetn(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x4EB4CAA: std::istream::read(char*, long) (in /usr/lib/x86_64-linux-gnu/libstdc++.so.6.0.19)
by 0x400EDD: searchInFile(long long) (test.cpp:30)
by 0x400FAA: displayRecord(long long) (test.cpp:55)
by 0x401300: main (test.cpp:92)
If you believe this happened as a result of a stack
overflow in your program's main thread (unlikely but
possible), you can try to increase the size of the
main thread stack using the --main-stacksize= flag.
The main thread stack size used in this run was 8388608.
HEAP SUMMARY:
in use at exit: 8,760 bytes in 2 blocks
total heap usage: 4 allocs, 2 frees, 17,520 bytes allocated
LEAK SUMMARY:
definitely lost: 0 bytes in 0 blocks
indirectly lost: 0 bytes in 0 blocks
possibly lost: 0 bytes in 0 blocks
still reachable: 8,760 bytes in 2 blocks
suppressed: 0 bytes in 0 blocks
ERROR SUMMARY: 2 errors from 2 contexts (suppressed: 0 from 0)
Segmentation fault (core dumped)
请注意,每次运行前都删除了test.dat文件。
Program received signal SIGSEGV, Segmentation fault.
0x00007ffff7b7338e in std::basic_streambuf<char, std::char_traits<char> >::xsgetn(char*, long) () from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
(gdb) bt
#0 0x00007ffff7b7338e in std::basic_streambuf<char, std::char_traits<char> >::xsgetn(char*, long) () from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#1 0x00007ffff7b88d0e in std::basic_filebuf<char, std::char_traits<char> >::xsgetn(char*, long) () from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#2 0x00007ffff7b54cab in std::istream::read(char*, long) () from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#3 0x0000000000400ede in searchInFile (phoneNo=9988776655) at test.cpp:30
#4 0x0000000000400fab in displayRecord (phoneNo=9988776655) at test.cpp:55
#5 0x0000000000401301 in main () at test.cpp:92
我唯一能想到的是buffer
正在写进入这里,但这并不能让我在任何地方。
答案 0 :(得分:1)
read()方法将读取的信息写入缓冲区, 而且我怀疑valgrind认为这封写无效, 所以开始看看你的缓冲区是如何分配的。
在这种情况下,valgrind显然是正确的。您需要分配内存来缓冲它以将文件内容放入。
例如
record * buffer = new record;
答案 1 :(得分:0)
buffer
为空。您没有将任何存储分配到read
,传递错误的大小(它应该是0,而不是sizeof(record)
)并在以后取消引用它会导致未定义的行为。 valgrind中的write
和read
指的是内存访问,而不是文件读取或写入。