Question

我有一个Spring boot 1.5.2的问题，我还添加了JSP的所有依赖项，因此它可以从web应用程序（war）文件返回。

application.properties

spring.mvc.view.prefix: /WEB-INF/jsp/
spring.mvc.view.suffix: .jsp

带有JSP依赖关系的pom.xml

<!-- JSTL for JSP -->
    <dependency>
        <groupId>javax.servlet</groupId>
        <artifactId>jstl</artifactId>
    </dependency>

    <!-- Need this to compile JSP -->
    <dependency>
        <groupId>org.apache.tomcat.embed</groupId>
        <artifactId>tomcat-embed-jasper</artifactId>
        <scope>provided</scope>
    </dependency>

    <!-- Need this to compile JSP,
    tomcat-embed-jasper version is not working, no idea why -->
    <dependency>
        <groupId>org.eclipse.jdt.core.compiler</groupId>
        <artifactId>ecj</artifactId>
        <version>4.6.1</version>
        <scope>provided</scope>
    </dependency>

我有一个像这样的简单控制器

@Controller
public class ClassController {
    @RequestMapping("/**")
    public String handle(HttpServletRequest req, HttpServletResponse resp) throws ServletException, IOException {
       // This one can handle any rest URIs, e.g: localhost:8080/application/abc, localhost:8080/application/abc/12/asdasd/3123,...
    }
}

但是，我无法从localhost：8080 / application / index.jsp返回index.jsp，因为它不会调用方法句柄，而是返回

Whitelabel Error Page

This application has no explicit mapping for /error, so you are seeing this as a fallback.

Mon Oct 02 10:20:39 CEST 2017
There was an unexpected error (type=Not Found, status=404).

什么是正确的配置，所以我可以将.jsp（例如：http://localhost:8080/application/index.jsp）的请求指向jsp文件（WEB-INF / jsp / index.jsp）和REST uri（http://localhost:8080/application/132/21321312/324 ）处理方法？

Answer 1

我使用servlet过滤器将包含.jsp的请求转发到/ WEB-INF / jsp中的相应文件，从而解决了这个问题。其他请求将转到控制器内的handle（）方法。

 @WebFilter(urlPatterns = "/*")
public class SecoreFilter implements Filter {

    @Override
    public void doFilter(ServletRequest req, ServletResponse res,
            FilterChain chain) throws IOException, ServletException {

        HttpServletRequest request = (HttpServletRequest) req;
        HttpServletResponse response = (HttpServletResponse) res;
        if (!request.getRequestURI().endsWith(".jsp")) {
            chain.doFilter(req, res);
        } else {
            String jspFile = new File(request.getRequestURI()).getName();
            // e.g: /application/3223/234234/2342323/browse.jsp
            String uri = request.getRequestURI();
            // extract the jsp file from uri
            uri = uri.substring(0, uri.length() - jspFile.length());
            RequestDispatcher dispatcher = req.getServletContext()
                    .getRequestDispatcher("/WEB-INF/jsp/" + jspFile);
            req.setAttribute("uri", uri);
            dispatcher.forward(req, response);
            // chain.doFilter(req, res);
        }
    }

    @Override
    public void destroy() {
    }

    @Override
    public void init(FilterConfig arg0) throws ServletException {
    }

}

Answer 2

我根据您的描述重建了您的项目，发现了两个问题。

tomcat-embed-jasper 需要是编译时依赖项，您不需要Eclipse编译器
在控制器（ ClassController ）中，您必须返回视图的名称，即索引。

您可以在此处找到一个有效的示例：https://github.com/springuni/springuni-stackoverflow/tree/master/question-46521912

它的作用是将任何给定的请求（/ application / 132/21321312/324）重定向到 index.jsp 。在JSP中，请求的路径被写入输出，以证明重定向实际上来自控制器。

让我知道它是否适合你！

干杯，拉斯洛

Spring Boot - 映射JSP和REST URI以在控制器中处理的正确方法？

2 个答案: