使用javascript或jquery删除url参数

Question

我正在尝试使用youtube数据api生成视频播放列表。但是，视频网址需要使用youtube.com/watch?v=3sZOD3xKL0Y格式，但api生成的是youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata。所以我需要做的是能够选择＆符号之后的所有内容并将其从url中删除。使用javascript和某种正则表达式的任何方法吗？

Answer 1

我错过了什么？

为什么不：

url.split('?')[0] 

Answer 2

简单：

var new_url = old_url.substring(0, old_url.indexOf('?'));

修改：  这将从url中删除所有参数或片段

var oldURL = [YOUR_URL_TO_REMOVE_PARAMS]
var index = 0;
var newURL = oldURL;
index = oldURL.indexOf('?');
if(index == -1){
    index = oldURL.indexOf('#');
}
if(index != -1){
    newURL = oldURL.substring(0, index);
}

Answer 3

嗯......寻找更好的方法......这里是

var onlyUrl = window.location.href.replace(window.location.search,'');

Answer 4

示例： http://jsfiddle.net/SjrqF/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.slice( 0, url.indexOf('&') );

或：

示例： http://jsfiddle.net/SjrqF/1/

var url = 'youtube.com/watch?v=3sZOD3xKL0Y&feature=youtube_gdata';

url = url.split( '&' )[0];

Answer 5

//user113716 code is working but i altered as below. it will work if your URL contain "?" mark or not
//replace URL in browser
if(window.location.href.indexOf("?") > -1) {
    var newUrl = refineUrl();
    window.history.pushState("object or string", "Title", "/"+newUrl );
}

function refineUrl()
{
    //get full url
    var url = window.location.href;
    //get url after/  
    var value = url = url.slice( 0, url.indexOf('?') );
    //get the part after before ?
    value  = value.replace('@System.Web.Configuration.WebConfigurationManager.AppSettings["BaseURL"]','');  
    return value;     
}

Answer 6

使用此功能：

var getCleanUrl = function(url) {
  return url.replace(/#.*$/, '').replace(/\?.*$/, '');
};

// get rid of hash and params
console.log(getCleanUrl('https://sidanmor.com/?firstname=idan&lastname=mor'));

如果您想要所有href部件，请使用：

var url = document.createElement('a');
url.href = 'https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container';

console.log(url.href); // https://developer.mozilla.org/en-US/search?q=URL#search-results-close-container
console.log(url.protocol); // https:
console.log(url.host); // developer.mozilla.org
console.log(url.hostname); // developer.mozilla.org
console.log(url.port); // (blank - https assumes port 443)
console.log(url.pathname); // /en-US/search
console.log(url.search); // ?q=URL
console.log(url.hash); // #search-results-close-container
console.log(url.origin); // https://developer.mozilla.org

Answer 7

您可以使用RegEx来匹配v的值并自行构建网址，因为您知道网址是youtube.com/watch?v = ...

http://jsfiddle.net/akURz/

var url = 'http://youtube.com/watch?v=3sZOD3xKL0Y';
alert(url.match(/v\=([a-z0-9]+)/i));

Answer 8

好吧，我正在使用它：

stripUrl(urlToStrip){
        let stripped = urlToStrip.split('?')[0];
        stripped = stripped.split('&')[0];
        stripped = stripped.split('#')[0];
        return stripped;
    }

或：

    stripUrl(urlToStrip){
        return urlToStrip.split('?')[0].split('&')[0].split('#')[0];
    }

Answer 9

例如，我们有：

example.com/list/search?q=Somethink

您需要使用 window.location.href 这样的变量url：

example.com/list/edit

来自网址：

example.com/list/search?q=Somethink
example.com/list/

var url = (window.location.href);
    url = url.split('/search')[0];
    url = (url + '/edit');

这是简单的解决方案：-）

Answer 10

这对我有用：

window.location.replace(window.location.pathname)

Answer 11

<块引用>

没有 splits.. :) 正确/万无一失的方法是让原生浏览器 BUILT-IN functions 使用 urlParams 完成繁重的工作，繁重的工作已为您完成.

//summary answer - this one line will correctly replace in all current browsers
window.history.replaceState({}, '', `${location.pathname}?${params}`);

// 1 Get your URL 
let url = new URL('https://tykt.org?unicorn=1&printer=2&scanner=3');
console.log("URL: "+ url.toString());

// 2 get your params
let params = new URLSearchParams(url.search);
console.log("querys: " + params.toString());

// 3 Delete the printer param, Query string is now gone
params.delete('printer'); 
console.log("Printer Removed: " + params.toString()); 

// BELOW = Add it back to the URL, DONE!
___________

现在将所有内容整合到您的实时浏览器中

// Above is a breakdown of how to get your params
// 4 then you simply replace those in your current browser!! 
window.history.replaceState({}, '', `${location.pathname}?${params}`);

Sample working Javascript Fiddle here