Question

我想解析linux上的ssh配置文件，以获取 $ HOME / .ssh / config 中定义的每个主机的信息（主机名，用户）。我的想法是使用lua string.gmatch 使用Host作为分隔符来分割文件，但由于某种原因，模式匹配不起作用。这是来自lua解释器的代码

> =x
Host h1
Hostname ip1
User root
Host h2 h3
Hostname ip2
User admin
Host *
ControlPath xyz 

> for i in x:gmatch('(Host%s+.-)Host%s') do print(i) end
Host h1
Hostname ip1
User root

>

Answer 1

捕获由字母数字组成的主机名值，包括点，连字符和下划线。

x = [[Host h1
Hostname ip1
Host h2
Hostname ip2

Host *
ControlMaster auto]]

for i in x:gmatch("Hostname%s+([%w%.-_]+)") do
  print(i)
end

Answer 2

这是我对您的问题的完整解决方案。它从STDIN读取输入文件。像例如program.lua < /path/to/.ssh/config

那样运行它

--Example of SSH config file
--[[
Host h1
HostName ip1
User root
Host h2 h3
Hostname ip2
User admin
Host *
ControlPath xyz
--]]

local hostPattern = "Host%s+([%w%.-_]+)"
local hostNamePattern = "Host[Nn]ame%s+([%w%.-_]+)"
local userPattern = "User%s+([%w%.-_]+)"

local line = io.read("l")
while line do
    if line:find(hostPattern) then
        local host = line:match(hostPattern)
        local hostName, user

        line = io.read("l")
        while line do
            if line:find(hostPattern) then
                break
            elseif line:find(hostNamePattern) then
                hostName = line:match(hostNamePattern)
            elseif line:find(userPattern) then
                user = line:match(userPattern)
            end
            line = io.read("l")
        end
        io.write(string.format("%s: -> %s, %s", host, hostName, user))
    end
    io.write("\n")
end

这是你可以期待的输出：

h1: -> ip1, root
h2: -> ip2, admin

主机使用lua拆分ssh配置

2 个答案: