Question

我创建了一个返回字符串的函数，如下所示，但我想知道如何保留引号的双引号？

def quote_maker(quote, name, year):
''' (string, string, number)-> None
Returns a sentence displaying in what given year the
given name of a person said the given quote.
'''
return (' In '+ str(year) +', a person called '+ name +' said: '+ quote)

例如我的函数返回：

 quote_maker("Everything should be made as simple as possible but not simpler.", "Albert Einstein", 1933)

'In 1933, a person called Albert Einstein said: Everything should be made as simple as possible but not simpler.'

而不是:(带双引号）

'In 1933, a person called Albert Einstein said: "Everything should be made as simple as possible but not simpler."'

Answer 1

您可以转义具有特殊含义的字符（使用\完成）以将其视为字符：

" this is quoted: \"example\" "

表示字符串：

引用：“示例”

Answer 2

我认为最好的方法是使用字符串格式化。并返回变量。

sentence = 'In {0}, a person called {1} said: "{2}".'.format(year, name, quote)

对于复杂的字符串，您应该使用转义字符。有关详细信息enter link description here

返回return语句中的引号

2 个答案: